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dangina [55]
2 years ago
14

In a game using a spinner with five equal parts numbered 1 to 5, a contestant wins when the spinner lands on an odd number. Is t

his game fair?
A. yes
B. no
C. not enough information
Mathematics
1 answer:
gayaneshka [121]2 years ago
3 0

Answer:

A. yes

Step-by-step explanation:

The contestant has a 60% chance of winning because they could either spin 1, 3, or 5.

However, unless there's another player who can only spin evens, it's not fair, because the contestant who spins odds has a 60% chance, while this player will only have a 40% chance.

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If a = 12 and B = 43 degrees, find c.
ludmilkaskok [199]

Answer:

74

Step-by-step explanation:

You subtract 43 from 12 you get 31 then you add 43 and 31 you get 74 bye

8 0
3 years ago
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I’m crying helppppppppppppppppppppppp what is 5/10 times 2/4 show step by step and simplified
mamaluj [8]
Simplify both to 1/2 because both numerators are half of their denominators. Then multiply straight across to 1/4.
4 0
2 years ago
Find the perimeter of the composite figure.
iVinArrow [24]

Answer:

87.92

Step-by-step explanation:

you have to multiply 3.14 by 2 which will give you 6.28, then you multiply 6.28 by 14 which gives you 87.92. hope this helps

4 0
3 years ago
Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop
xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

 f(x)=log (3 x) +5 x²

f'(x)=\frac{1}{3x}+10 x

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

  x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248

x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012

x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057

x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052

So, root of the equation =0.205 (Approx)

Approximate relative error

                =\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41

 Approximate relative error in terms of Percentage

   =0.41 × 100

   = 41 %

7 0
2 years ago
Solve by using tables. Give each answer to at most two decimal places. –2x2 – 4 = –8x (1 point) 0.59, 3.41 –3.41, –0.59 1.17, 6.
Paul [167]
The answer is ou need to rewrite the equation to make it easy... and let it equal zero <span>2<span>x2</span>−8x+4=0</span> which will become <span>2(<span>x2</span>−4x+2)=0</span> you need to solve <span><span>x2</span>−4x+2=0</span><span> by completing the square or the general quadratic formula.</span>
7 0
3 years ago
Read 2 more answers
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