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3 years ago

Graph the set of points. which model is most appropriate for the set (-6 4) (-4 0) (-3 -2) (-1 -7)

Mathematics

1 answer:

Free_Kalibri [48]3 years ago

8 0

Answer:

The linear regression model is $y=-2.19x-8.92$ .

Step-by-step explanation:

The given data points are (-6 4) (-4 0) (-3 -2) (-1 -7). Plot these points on a coordinate plane.

From the graph it is clear that the point are in the form of a straight line, so we need to use the linear regression model.

The general linear regression model is

$y=ax+b$

Using technology we get

$a=-2.1923076923\approx -2.19$

$b=-8.9230769231\approx -8.92$

Put a=-2.19 and b=-8.92 in the above equation.

$y=-2.19x-8.92$

Therefore the linear regression model is $y=-2.19x-8.92$ .

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Find the slope, or rate of change, from the graph.

TEA [102]

Answer:

-1/2

Step-by-step explanation:

slope is rise over run

or y change divided by x change

to find the slope you need to find points on the graph that meet exact points on the graph

i see (0,1) and (2,0)

to find slope without graph it would be (y2-y1)/(x2-x1)

in this case (0-1)/(2-0)

=-1/2

with graph you can count that it goes down -1 squares and to the right 2 squares

hope this helps

4 0

3 years ago

Read 2 more answers

G(x) = -2x^3 – 15x^2 + 36x

shusha [124]

Consider the function $G(x) = -2x^3 - 15x^2 + 36x.$ First, factor it:

$G(x) = -2x^3 - 15x^2 + 36x=-x(2x^2+15x-36)=\\ \\=-x\cdot 2\cdot \left(x-\dfrac{-15-\sqrt{513}}{4}\right)\cdot \left(x-\dfrac{-15+\sqrt{513}}{4}\right).$

The x-intercepts are at points $\left(\dfrac{-15-\sqrt{513} }{4},0\right),\ (0,0),\ \left(\dfrac{-15+\sqrt{513} }{4},0\right).$

1. From the attached graph you can see that

function is positive for $x\in \left(-\infrty, \dfrac{-15-\sqrt{513} }{4}\right)\cup \left(0,\dfrac{-15+\sqrt{513} }{4}\right);$
function is negative for $x\in \left(\dfrac{-15-\sqrt{513} }{4},0\right)\cup \left(\dfrac{-15+\sqrt{513} }{4},\infty\right).$

2. Since

$G(-x) = -2(-x)^3 - 15(-x)^2 + 36(-x)=2x^3-15x^2-36x\neq G(x)\ \text{and }\neq -G(x)$ the function is neither even nor odd.

3. The domain is $x\in (-\infty,\infty),$ the range is $y\in (-\infty,\infty).$

8 0

3 years ago

Read 2 more answers

Please answer this correctly

Lynna [10]

Answer:

75%

Step-by-step explanation:

There is 1 whisker and quartiles 1-3 so:

25%+25%+25%=75%

6 0

3 years ago

For brainiest:):):):):):):):)

olga2289 [7]

Here is the answer to ur question :) Hope this helps!

7 0

3 years ago

What is the answer to A and B?

Alex_Xolod [135]

For A) u must start at -3 on y lines. Then move points up 1 and 3 to the right. Makes point and continue to make lines
For B) start at 5 on y lines, and remember -x is same thing is -1. And negative means go down! So move 1 down and 1 to the right and make point then move 1 down and make 1 right and make second points and continue. Draw a lines.

The solution is when u see two lines from two equations crosses to each other. There’s solution shown.

3 0

3 years ago