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3 years ago

Numbers 16 && 18 please??

Mathematics

1 answer:

Len [333]3 years ago

3 0

16.

{ (6x^3)/(3x^4)}^2

= (2/x)^2

=(4)/(x^2)

so, option A is correct

18.

option C is the correct one.

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A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the

Anastasy [175]

Answer: 19.4

Step-by-step explanation:

Given

Profit is given in terms of the selling price

$y=-5x^2+194x-900$

to get the maximum price, differentiate y w.r.t x

$\frac{\mathrm{d} y}{\mathrm{d} x}=-5\times 2x+194$

Put $\frac{\mathrm{d} y}{\mathrm{d} x}=0$ to get maximum value

$10x=194\\x=19.4$

Thus, the company must sell it at 19.4

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2 years ago

Solve the inequality 15 ≥ q + 3

oksano4ka [1.4K]

Answer:

$q\le \:12$

Step-by-step explanation:

Solving

$\mathrm{Switch\:sides}$ (Not a required step)

$q+3\le \:15$

$\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}$

$q+3-3\le \:15-3\\=q\le \:12$

$\bold{q\le \:12}$

Graphing

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2 years ago

Passes through the points (−4, 2) and (12, 6)?

svlad2 [7]

I'll assume you need to find the equation of the line that passes through those points.

Answer:

$\displaystyle y-2=\frac{1}{4}(x+4)$

Step-by-step explanation:

Equation of a Line:

The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:

$\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

The given points are (-4,2) and (12,6), thus:

$\displaystyle y-2=\frac{6-2}{12+4}(x+4)$

Operating:

$\displaystyle y-2=\frac{4}{16}(x+4)$

Simplifying, the equation in point-slope form is:

$\mathbf{\displaystyle y-2=\frac{1}{4}(x+4)}$

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2 years ago

Malcolm solves w2-3w=350

stiv31 [10]

Answer:

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2 years ago

Devy likes to learn! Could someone please tell me how to answer this question?

Ronch [10]

Answer:

Step-by-step explanation:

Recall that if two functions, f and g, are inverses, then by definition:

$\displaystyle f(g(x)) = g(f(x)) = x$

Hence, the graph of f(g(x)) should be simply y = x.

Therefore, our answer is B, as both coordinates are equivalent for all three points.

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3 years ago