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kiruha [24]
3 years ago
11

What is it? A or B I've been stuck for a while please help

Mathematics
2 answers:
AlladinOne [14]3 years ago
3 0

Answer:

<em>Correct choice: B</em>

Step-by-step explanation:

<u>System of non-linear equations</u>

It's given the following system of equations:

y=x^2+3x+5

y=x+13

We'll use the substitution method. Substituting y from the first equation into the second equation, we have:

x^2+3x+5=x+13

Moving all terms to the left side:

x^2+3x+5-x-13=0

Simplifying:

x^2+2x-8=0

Factoring:

(x+4)(x-2)=0

There are two solutions:

x=-4, x=2

The first solution gives a value for y:

y=-4+13=9

First solution: (-4,9)

The second solution gives a value for y:

y=2+13=15

Second solution: (2,15)

Correct choice: B

Rzqust [24]3 years ago
3 0
I think the correct answer choice is B
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Tangent Line h(t) = sec t / t @ (Pi, 1/pi)
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Take derivitive

note
the derivitive of sec(x)=sec(x)tan(x)
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remember the quotient rule
the derivitive of \frac{f(x)}{g(x)} = \frac{f'(x)g(x)-g'(x)f(x)}{(g(x))^2}
so

the derivitive of \frac{sec(t)}{t} = \frac{sec(t)tan(t)t-(1)(sec(t))}{t^2}
so now evaluate when t=pi
we get
sec(pi)=-1
tan(pi)=0
we get
\frac{(-1)(0)(pi)-(pi)(-1)}{pi^2}= \frac{pi}{pi^2}= \frac{1}{pi}
slope=1/pi

use slope point form
for
slope=m and point is (x1,y1)
equation is
y-y1=m(x-x1)
slope is 1/pi
point is (pi,1/pi)

y-1/π=1/π(x-π)
times both sides by π
πy-1=x-π
πy=x-π+1
y=(1/π)x-1+(1/π)
or, alternately
-(1/π)x+y=(1/π)-1
x-πy=π-1
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Answer:

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Step-by-step explanation:

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Answer:

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