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Juliette [100K]
2 years ago
6

Find the volume of this cylinder give your answer to 1dp 20cm 9cm

Mathematics
1 answer:
vlada-n [284]2 years ago
5 0

Answer:

this is a required answer.

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James works as a waiter. He served meals with bills of $23.59, $40.65, $30.50, and $15.68. If his total for tips was $17.67, wha
SIZIF [17.4K]

Answer:

16%

Step-by-step explanation:

To find the percent, add the total for each meal to find the total dollars spent.

23.59 + 40.65 + 30.50 + 15.68 = 110.42

Divide the tip amount 17.67 by 110.42.

17.67/110.42 = 0.16

Multiply the decimal by 100 to convert to a percent.

0.16*100 = 16%

6 0
3 years ago
Stella has points card for a movie theater
Basile [38]
Answer:
12.5v+25=130
v=8.4
You can’t visit 8.4 times. So you would need to visit 9 times to get a sufficient amount for a ticket.
4 0
2 years ago
Prove the identity (cosx+cosy)^2+(sinx-siny)^2= 2+2cos(x+y)
astra-53 [7]
(cos(x) + cos(y))^2 + (sin(x) - sin(y))^2 Remove the brackets

cos^2(x)
+ cos^2(y) + 2cos(x)*cos(y) + sin^2(x) - 2(sin(x)*sin(y) + sin^2(y) Combine these two in bold to make 1 because sin^2(x) + cos^2(x) = 1

1 + cos^2(y) + 2cos(x)*cos(y) - 2*sin(x)*cos(y) + sin^2(y) 
These two in bold also make 1

2 + 2cos(x)*cos(y) - 2*sin(X)*sin(y) Bring out a common factor of 2
2 +2(cos(x)*cos(y) -  sin(x)*sin(y) )

but cos(x+y ) = cos(x)*cos(y) - sin(x)*sin(y)

2 + 2* cos(x + y) is your final answer. 

4 0
3 years ago
Read 2 more answers
What is the solution to {2x +3y=11 and 3x+3y=18
ra1l [238]

Answer:

The ordered pair that satisfies the equation is (7, -1)

Step-by-step explanation:

In order to find this, we can solve by subtracting. Start by stacking the two equations on top of one another and subtracting like terms.

3x + 3y = 18

(-) 2x + 3y = 11

--------------------

x = 7

Now that we have the value for x, we can plug in to either equation to find y.

2x + 3y = 11

2(7) + 3y = 11

14 + 3y = 11

3y = -3

y = -1

5 0
3 years ago
Please help me ASAP!!
olya-2409 [2.1K]

Answer:

17.6

Step-by-step explanation:

3 0
3 years ago
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