Evaluate when y=4 and 1 = 2 xy + 2x2

Mathematics

1 answer:

Zielflug [23.3K]4 years ago

6 0

Answer:

log ( 100 ) √ 16 √ 75

Step-by-step explanation:

You might be interested in

Can anyone please help me this? stuck with this problem for hours

Art [367]

First time the area of the circle and the square.
The radius of the first is 4, so the area of the circle is 16pi.
The area of the square is 32.
You can subtract the area of the circle by the square because some most of the circle is being covered by the square.
16pi-32 is the area of the circle that is visible.
16pi-32:32 can be simplified to pi-2:2
So the probability that a randomly selected point within the circle falls in the white area is
pi-2:2 or in decimal terms, ≈1.14:2

3 0

4 years ago

Read 2 more answers

which is a correct first step in solving the inequality –4(2x – 1) > 5 – 3x? distribute –4 to get –8x 4 > 5 – 3x. distribu

dolphi86 [110]

Distribute -4 in this way:

-4(2x) - 4(-1) > 5 - 3x, to get

- 8x + 4 > 5 - 3x

8 0

3 years ago

Read 2 more answers

Please answer both questions math

djyliett [7]

Answer:

$3$ and perpendicular

Step-by-step explanation:

It's important to remember that equations of lines are always set up in the format of $y=mx+c$ .

$y$ is the $y$ value, $m$ is the gradient/slope, $x$ is the $x$ value and $c$ is the y-intercept.

Therefore, we must always rearrange our line equations so that $y$ is the subject.

In the first question, we are given the equation $2x+6y=12$ .

We rearrange to make $y$ the subject:

$6y = 12-2x$

Then, we divide both sides by 6 to have the $y$ isolated:

$\frac{6}{6} y = \frac{12}{6} - \frac{2}{6}x\\\\ y = 2 - \frac{1}{3}x$

To find a perpendicular slope, we use the negative reciprocal of the original slope. The negative part of that means we negate the value (it becomes inverse) and the reciprocal part means that we flip the fraction.

So here, the slope is $-\frac{1}{3}$ .

So, the negative reciprocal of that would be $3$ because we inverse the sign (the negative becomes positive) and the fraction is flipped to create $\frac{3}{1}=3$ .

So, the perpendicular slope is $3$ .

In the second question, we have two equations. They both need to be rearranged to isolate the $y$ .

$4x-y=5\\4x = 5 + y\\y = 4x - 5\\\\4y = -x-12\\y = -\frac{1}{4}x - 3$

Look at the slopes of the two equations. If you look carefully, you will see that they are inverse of each other (one is positive and one is negative) and if you imagine $4 = \frac{4}{1}$ , the fraction is flipped.