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3 years ago

Anyone know the answer

Mathematics

1 answer:

Fed [463]3 years ago

6 0

Answer:

It is 2 miles per hour

Step-by-step explanation:

Because you divided 6 and 3

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2x+3y=1, -x+2y=-4 solve using substitution method

ollegr [7]

Step-by-step explanation:

1) 2x+3y-3y=1-3y. -x+2y= -4

2x/2=1-3y/2. -(1-3y/2)=-4

x=1-3y/2. -1+3y/2= -4

x=1-3(-2)/2 3y/2= -4+1

x=1+6/2 3y/2×2/3= -3×2/3

x=7/2 y= -2

S.s{ 7/3,-2}

2). -4x-6y+6y=7-6y. 4x+y= -2

-4x/-4=7-6y/-4. 4(-7-6y/4)+y= -2

x= -7-6y/4. -7-6y+y = -2

x= -7-6/4 -5y/5= 5/5

x=-13/4 y= 1

S.s { -13/4, 1 }

8 0

3 years ago

What's 0.875 as a fraction in simplest form

zhenek [66]

$0.875=\dfrac{875}{1000}=\dfrac{875:25}{1000:25}=\dfrac{35:5}{40:5}=\boxed{\frac{7}{8}}$

8 0

3 years ago

URGENT! WILL GIVE BRAINLIEST!!

IgorC [24]

Answer:

Option C) $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is not the correct way to define the given infinite sequence

${\{m+b,2m+b,3m+b,4m+b,...}\}$

Step-by-step explanation:

Given infinite sequence is ${\{m+b,2m+b,3m+b,4m+b,...}\}$

Option B) $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is not the correct way to define the given infinite sequence ${\{m+b,2m+b,3m+b,4m+b,...}\}$

Now verify $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is true for the given infinite sequence

That is put n=1,2,3,.. in the above function

$a_{n}=m-b+m(n-1)$

When n=1, $a_{1}=m-b+m(1-1)$

$=m-b+0$

$a_{1}=m-b\neq m+b$

When n=2, $a_{2}=m-b+m(2-1)$

$=m-b+m$

$a_{2}=2m-b\neq 2m+b$

When n=3, $a_{3}=m-b+m(3-1)$

$=m-b+2m$

$a_{3}=3m-b\neq 3m+b$

and so on.

Therfore $a_{n}=m-b+m(n-1)$ for $n={\{1,2,3,...}\}$ is not the correct way to define the given infinite sequence

${\{m+b,2m+b,3m+b,4m+b,...}\}$

Therefore option C) is correct

5 0

4 years ago

A tuning fork is struck and oscillates in damped harmonic motion. The amplitude of the motion is measured, and 3 s later it is f

attashe74 [19]

Answer:

C=0.46 s⁻¹

Step-by-step explanation:

The general equation for the damped harmonic system given as

$y=Xe^{-Ct}sin\omega t$

Where

A= Amplitude

$A=Xe^{-Ct}$

C=Damping constant

Lets take at time t= t₁, A= K

And at time t= t₁+3 s ,A= K/4

$A=Xe^{-Ct}$

$K=Xe^{-Ct_1}$ -----------1

$\dfrac{K}{4}=Ke^{-C(t_1+3)}$ -------------2

From equation 1 and 2

$Xe^{-Ct_1}=Ke^{-C(t_1+3)}$

$1=4e^{-3C}$

$e^{3C}=4$

$C=\dfrac{1}{3}\ln4$

C=0.46 s⁻¹

7 0

3 years ago

129.2 is 38% of what number? a. 340 b. 29.4 c. 420 d. 49.1 Plss help

Alexus [3.1K]

Answer: A 340

Step-by-step explanation:

129.2/0.38=340

5 0

3 years ago

Read 2 more answers