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Angelina_Jolie [31]
3 years ago
13

Find the measures of the supplementary angles if their difference is equal to 35°

Mathematics
1 answer:
skad [1K]3 years ago
5 0

Set up a system of equations using the sum and difference equation.

    x + y = 180      <em>definition of supplementary angles</em>

+    <u>x - y = 35</u>  

     2x   = 215    

       x   = 107.5

x + y = 180  ⇒  107.5 + y = 180   ⇒   y = 72.5

Answer: 107.5 and 72.5

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If 2x-9=3x-26 then what is x
My name is Ann [436]
Answer: x=17

2x-9=3x-26
-2x -2x
———————
-9=1x-26
+26 +26
———————
17 = 1x
— —
1 1

17=x

5 0
3 years ago
Is 9-8x=y proportional
andrew-mc [135]

Answer:

No, proportional relations are of the form,

y = mx

Step-by-step explanation:

The given equation is

9 - 8x = y

This is an equation in the form:

y = mx + c

since we can rewrite to get:

y =  - 8x + 9

This equation has a non-zero y-intercept and does not pass through the origin.

A proportional relation, will have a zero y-intercept and pass through the origin.

Therefore a proportional relation is of the form,

y = mx

5 0
4 years ago
Place (dlick and drag) one option from each of the lists below Into Its corresponding box to
earnstyle [38]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{1}{3}}x+5\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-1}{3}} ~\hfill \stackrel{reciprocal}{\cfrac{3}{-1}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{3}{-1}\implies 3}}

so we're really looking for the equation of a line whose slope is 3 and passes through (1 , 10)

(\stackrel{x_1}{1}~,~\stackrel{y_1}{10})\qquad \qquad \stackrel{slope}{m}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{3}(x-\stackrel{x_1}{1}) \\\\\\ y-10=3x-3\implies y=3x+7

5 0
2 years ago
A batch of 40 parts contains six defects. If two parts are drawn randomly one at a time without replacement, what is the probabi
adell [148]

Answer:

a) Therefore, the probability is P=1/52.

b) Therefore, the probability is P=9/400.

Step-by-step explanation:

We know that a  batch of 40 parts contains six defects.

a) We calculate the probability that the both parts are defective, if two parts are drawn randomly one at a time without replacement.

The probability for the first is 6/40.

The probability for the second is 5/39.  

We get:

P=\frac{6}{40}\cdot \frac{5}{39}\\\\P=\frac{1}{52}

Therefore, the probability is P=1/52.

b) We calculate the probability that the both parts are defective, if two parts are drawn randomly one at a time with replacement.

The probability for the first is 6/40.

The probability for the second is 6/40.  

We get:

P=\frac{6}{40}\cdot \frac{6}{40}\\\\P=\frac{9}{400}

Therefore, the probability is P=9/400.

6 0
3 years ago
At Saturday night’s football game there were 18 less fans than half the fans at Friday night’s game. There were “x” fans at Frid
Valentin [98]
X divided by 2 take away 18 hope it helps.
7 0
3 years ago
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