Answer:
The outer circle is 16 feet larger than the inner circle (68 - 52).
Step-by-step explanation:
Given that the inner circle circumference is 52 feet, and the distance between the inner and the outer circle is 8 feet, to determine by how many ft is the larger outer circle, the following calculation must be performed:
The radius of a circle is equal to half its diameter. Therefore, the radius of the inner circle is 26 feet. Thus, if the distance between the two circles is 8 feet, the radius of the outer circle is 34 feet (26 + 8). Therefore, the diameter of this circle is 68 feet (34 x 2).
This implies that the outer circle is 16 feet larger than the inner circle (68 - 52).
For this case we model the problem as a rectangle.
The area of the rectangle is given by:
A = (w) * (l)
Where,
w: width
l: long
Substituting values we have:
4800 = (w) * ((1 1/3) * w)
We rewrite:
w ^ 2 = 4800 / (1 1/3)
w ^ 2 = 3600
w = root (3600)
w = 60 in
The long will be then:
l = (1 1/3) * w
l = (1 1/3) * (60)
l = 80 in
Answer:
the dimensions of the quilt are:
w = 60 in
l = 80 in
Point form: (6,-3)
equation form: x=6, y=-3
Answer:
C and E would be your Answer!
Answer:
0.28 liters
Step-by-step explanation:
104÷365=0.28
