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Katyanochek1 [597]

3 years ago

13

In a for loop, is it possible to use indexing?

1 answer:

kenny6666 [7]3 years ago

4 0

Answer:

Yes

Step-by-step explanation:

A for loop basically relies on repeating the same code for a pre-set number of times. During which you can make any code repeat inside of it, including indexing through a type of list. Many times a for-loop will use the indexes in a list to calculate the number of times that the loop has to repeat. This is usually done in order to search or apply changes in an array of other types of data structures that have countless values stored in it.

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Hey can someone tell me what -3x^2(14x^2-2x-8) equals

Ad libitum [116K]

Answer:

-42x^4 + 6x^3 + 24x^2

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Assume that X is normally distributed with a mean of 20 and a standard deviation of 2. Determine the following. (a) P(X 24) (b)

Tems11 [23]

Answer:

a) P( X < 24 ) = 0.9772

b) P ( X > 18 ) =0.8413

c) P ( 14 < X < 26) = 0.9973

d) P ( 14 < X < 26) = 0.9973

e) P ( 16 < X < 20) = 0.4772

f) P ( 20 < X < 26) = 0.4987

Step-by-step explanation:

Given:

- Mean of the distribution u = 20

- standard deviation sigma = 2

Find:

a. P ( X < 24 )

b. P ( X > 18 )

c. P ( 18 < X < 22 )

d. P ( 14 < X < 26 )

e. P ( 16 < X < 20 )

f. P ( 20 < X < 26 )

Solution:

- We will declare a random variable X that follows a normal distribution

X ~ N ( 20 , 2 )

- After defining our variable X follows a normal distribution. We can compute the probabilities as follows:

a) P ( X < 24 ) ?

- Compute the Z-score value as follows:

Z = (24 - 20) / 2 = 2

- Now use the Z-score tables and look for z = 2:

P( X < 24 ) = P ( Z < 2) = 0.9772

b) P ( X > 18 ) ?

- Compute the Z-score values as follows:

Z = (18 - 20) / 2 = -1

- Now use the Z-score tables and look for Z = -1:

P ( X > 18 ) = P ( Z > -1) = 0.8413

c) P ( 18 < X < 22) ?

- Compute the Z-score values as follows:

Z = (18 - 20) / 2 = -1

Z = (22 - 20) / 2 = 1

- Now use the Z-score tables and look for z = -1 and z = 1:

P ( 18 < X < 22) = P ( -1 < Z < 1) = 0.6827

d) P ( 14 < X < 26) ?

- Compute the Z-score values as follows:

Z = (14 - 20) / 2 = -3

Z = (26 - 20) / 2 = 3

- Now use the Z-score tables and look for z = -3 and z = 3:

P ( 14 < X < 26) = P ( -3 < Z < 3) = 0.9973

e) P ( 16 < X < 20) ?

- Compute the Z-score values as follows:

Z = (16 - 20) / 2 = -2

Z = (20 - 20) / 2 = 0

- Now use the Z-score tables and look for z = -2 and z = 0:

P ( 16 < X < 20) = P ( -2 < Z < 0) = 0.4772

f) P ( 20 < X < 26) ?

- Compute the Z-score values as follows:

Z = (26 - 20) / 2 = 3

Z = (20 - 20) / 2 = 0

- Now use the Z-score tables and look for z = 0 and z = 3:

P ( 20 < X < 26) = P ( 0 < Z < 3) = 0.4987

8 0

3 years ago

Jamie says that if she knows only the measure of one angle in an isosceles triangle, she can always determine the measures of th

lozanna [386]

Answer:

Jamie is correct

Step-by-step explanation:

Jamie is correct.

Example: isosceles triangle ABC AB=AC

∠B = ∠C ∠A + ∠B + ∠C = 180°

if ∠A = x ∠B = ∠C = 1/2 * ( 180° - x)

if ∠B or ∠C = x ∠A = 180° - 2x

6 0

3 years ago

Read 2 more answers

Lengths of full-term babies in the US are Normally distributed with a mean length of 20.5 inches and a standard deviation of 0.9

mash [69]

Answer:

66.48% of full-term babies are between 19 and 21 inches long at birth

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean length of 20.5 inches and a standard deviation of 0.90 inches.

This means that $\mu = 20.5, \sigma = 0.9$

What percentage of full-term babies are between 19 and 21 inches long at birth?

The proportion is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19. Then

X = 21

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{21 - 20.5}{0.9}$

$Z = 0.56$

$Z = 0.56$ has a p-value of 0.7123

X = 19

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{19 - 20.5}{0.9}$

$Z = -1.67$

$Z = -1.67$ has a p-value of 0.0475

0.7123 - 0.0475 = 0.6648

0.6648*100% = 66.48%

66.48% of full-term babies are between 19 and 21 inches long at birth

5 0

2 years ago

Determine the vertical asymptote for the rational function f(x) = x - 4 over 2x + 3.

mr_godi [17]

Vertical asymptotes happen at x=a if the function is undefined at x=a.

This is a rational functions, and rational functions are not defined when the denominator is zero, since you can't divide by zero.

In this case, the denominator is zero if

$2x+3=0 \iff 2x=-3 \iff x=-\drac{3}{2}$

And thus the function has a vertical asymptote at x= -3/2

3 0

3 years ago