Answer:
2. angle bisector splits into even halves
Step-by-step explanation:
that's all i can assist with sorry, proofs still confuse me!
Answer: B
Step-by-step explanation: A function is a relation in which each input value is paired to exactly one output value.
Technically, if you had the same input value twice and the same output value corresponded to each of those, it would still be a function because you are just repeating what you have twice.
However, most teachers want to think of it as each input value must have exactly one corresponding value to be a function.
Answer:
15/24
Step-by-step explanation:
hope this helps u.
Answer:
See explanation
Step-by-step explanation:
In ΔABC, m∠B = m∠C.
BH is angle B bisector, then by definition of angle bisector
∠CBH ≅ ∠HBK
m∠CBH = m∠HBK = 1/2m∠B
CK is angle C bisector, then by definition of angle bisector
∠BCK ≅ ∠KCH
m∠BCK = m∠KCH = 1/2m∠C
Since m∠B = m∠C, then
m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)
Consider triangles CBH and BCK. In these triangles,
- ∠CBH ≅ ∠BCK (from equality (*));
- ∠HCB ≅ ∠KBC, because m∠B = m∠C;
- BC ≅CB by reflexive property.
So, triangles CBH and BCK are congruent by ASA postulate.
Congruent triangles have congruent corresponding sides, hence
BH ≅ CK.