The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C
From Newton's law of cooling, we have that

Where





From the question,


∴ 

Therefore, the equation
becomes

Also, from the question
After 1 hour, the temperature of the ice-cream base has decreased to 58°C.
That is,
At time
, 
Then, we can write that

Then, we get

Now, solve for 
First collect like terms


Then,


Now, take the natural log of both sides


This is the value of the constant 
Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at 
From

Then






Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C
Learn more here: brainly.com/question/11689670
Answer:
1
Step-by-step explanation:
that is the answer
because 51213÷3=17071
Answer:
20 Units
Step-by-step explanation:
Hight times length/by half is tribular prism Formula
Answer:
yp = -x/8
Step-by-step explanation:
Given the differential equation: y′′−8y′=7x+1,
The solution of the DE will be the sum of the complementary solution (yc) and the particular integral (yp)
First we will calculate the complimentary solution by solving the homogenous part of the DE first i.e by equating the DE to zero and solving to have;
y′′−8y′=0
The auxiliary equation will give us;
m²-8m = 0
m(m-8) = 0
m = 0 and m-8 = 0
m1 = 0 and m2 = 8
Since the value of the roots are real and different, the complementary solution (yc) will give us
yc = Ae^m1x + Be^m2x
yc = Ae^0+Be^8x
yc = A+Be^8x
To get yp we will differentiate yc twice and substitute the answers into the original DE
yp = Ax+B (using the method of undetermined coefficients
y'p = A
y"p = 0
Substituting the differentials into the general DE to get the constants we have;
0-8A = 7x+1
Comparing coefficients
-8A = 1
A = -1/8
B = 0
yp = -1/8x+0
yp = -x/8 (particular integral)
y = yc+yp
y = A+Be^8x-x/8