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Elenna [48]
4 years ago
10

Does anyone know the answer?

Mathematics
1 answer:
ozzi4 years ago
8 0
Maybe d. but u should probably wait for another answer
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The radio station gave away a discount coupon for every twelfth and thirteenth caller. Every twentieth caller received free conc
Snezhnost [94]

Answer:

60th caller.

the 12th caller would hit a number divisible by 20 at 60.

12,24,35,48,60

7 0
3 years ago
Michael's car can travel 25 miles on one gallon of gas. The cost of gas is $3.75 per gallon. Which equation could calculate the
Sedaia [141]
T = 3.75n over 25 (make it a fraction)
6 0
3 years ago
If x is a number that satisfies 4x+3=18, can x be equal to 3? explain.
Akimi4 [234]
The answer is no. because is you substitute the value 3 in for x into the equation and solve you get,

4(3)+3=18 which says 12+3=18 15=18 and that is an untrue statement. 
Hope this helps explain the concept so you understand! Any questions feel free to ask! Please rate if I helped you! thank you so much!!
4 0
3 years ago
Read 2 more answers
Evaluate the expression xy-3x; when x=4 and y=5. Pls provide explanation. Will choose brainliest.
Iteru [2.4K]

4*5-3*4

20-12

=8

Just plug in the numbers and solve. Remember that you multiply before you subtract.

7 0
3 years ago
R = sec(θ) − 2cos(θ), where -π/2 < θ < π/2
Alex

Answer:

  y = (x/(1-x))√(1-x²)

Step-by-step explanation:

The equation can be translated to rectangular coordinates by using the relationships between polar and rectangular coordinates:

  x = r·cos(θ)

  y = r·sin(θ)

  x² +y² = r²

__

  r = sec(θ) -2cos(θ)

  r·cos(θ) = 1 -2cos(θ)² . . . . . . . . multiply by cos(θ)

  r²·r·cos(θ) = r² -2r²·cos(θ)² . . . multiply by r²

  (x² +y²)x = x² +y² -2x² . . . . . . . substitute rectangular relations

  x²(x +1) = y²(1 -x) . . . . . . . . . . . subtract xy²-x², factor

  y² = x²(1 +x)/(1 -x) = x²(1 -x²)/(1 -x)² . . . . multiply by (1-x)/(1-x)

  \boxed{y=\dfrac{x\sqrt{1-x^2}}{1-x}}

__

The attached graph shows the equivalence of the polar and rectangular forms.

4 0
3 years ago
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