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Brut [27]
3 years ago
10

If your front lawn is 16.016.0 feet wide and 20.020.0 feet long, and each square foot of lawn accumulates 13501350 new snowflake

s every minute, how much snow, in kilograms, accumulates on your lawn per hour? Assume an average snowflake has a mass of 2.20 mg.
Physics
1 answer:
asambeis [7]3 years ago
4 0

Answer:

The mass of snow accumulated in the lawn in 1 hour equals 57.024 kilograms

Explanation:

Given

Width of lawn = 16 feet

Length of lawn = 20 feet

Thus total area of lawn equals 16\times 20=320sq.feet\

Now it is given that 1 square foot accumulates 1350 new snowflakes each minute thus number of snowflakes accumulated by 320 square feet in 1 minute equals

320\times 1350=432000

Now it is given that average mass of each snowflake is 2.20mg=2.20\times 10^{-3}g=2.20\times 10^{-6}kg

Hence the mass accumulated per minute equals 432000\times 2.20\times 10^{-6}=0.9504kg

Now since there are 60 minutes in 1 hour thus the mass accumulated in 1 hour equals 0.9504kg\times 60=57.024kg

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To determine the coefficient of static friction between two materials, an engineer places a small sample of one material on a ho
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This question is incomplete, the missing image is uploaded along this answer.

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the coefficient of friction is 0.32

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we make use of kinematic equation of motion;

ω = ω₀ + ∝t

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f = Fc

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