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ladessa [460]
3 years ago
10

A student throws a baseball at a large gong 52 m away and hears the sound of the gong 1.73333 s later. The speed of sound in air

is 330 m/s.
What was the average speed of the base- ball on its way to the gong? (For simplicity, assume its trajectory to be a straight line.)
Physics
1 answer:
Arte-miy333 [17]3 years ago
3 0

Speed = 52/1.57576= 33 m/s

Explanation:

Distance = speed * time

Given , the distance traveled by the baseball = 52 m

Speed of sound in air = 330 m/s

Total time  = 1.73333 s .

Total time for the student to hear the sound of the gong is the sum of the time take for the baseball to reach the gong and the time taken by the sound to travel back.

Distance traveled by the sound is 52 m and the speed is 330 m/s

So time taken by the sound to travel back = distance traveled / the speed

=> time = 52/330 s = 0.15757 s

Time taken by the base ball to reach the gong is the total time - the time taken by the sound

=> time taken by base ball = 1.73333 - 0.15757 = 1.57576s

Speed of the base ball to reach the gong = distance / time

Speed = 52/1.57576= 33 m/s

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Answer:

9.12267515924 m/s²

Explanation:

Here the moment created by the wheels and the moment created by the center of gravity will balance each other.

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g = Acceleration due to gravity = 9.81 m/s²

a = Horizontal acceleration

The equation is of the form

mgd=Fh\\\Rightarrow mgd=mah\\\Rightarrow a=\dfrac{gd}{h}\\\Rightarrow a=\dfrac{9.81\times \dfrac{146\times 10^{-2}}{2}}{78.5\times 10^{-2}}\\\Rightarrow a=9.12267515924\ m/s^2

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A 2 kg object with a weight of 20 N is being pulled up by a rope with a tension of 12N what is the acceleration of the object
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Answer:

The object accelerates downward at 4 m/s² since the tension on the rope is less than weight of the object.

Explanation:

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tension on the rope, T = 12 N

The acceleration of the object is calculated by applying Newton's second law of motion as follows;

T = F + W

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Answer:

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