There are many options, let me tell you three
- how many square feet is your house
- <span>how tall you are in centimeters. use the yardstick to measure yourself then calculate it into centimeters
- </span>needing to find the area of a space in order to purchase a couch you need the yardstick
I hope these options are useful
The x becomes negative because the negative sign at the start of the parenthesis distributes to everything inside parenthesis so x becomes -x and the double negative becomes +6 so that is why
The question is find the height of the tree, given that at two points 65 feet apart on the same side of the tree and in line with it, the angles of elevaton of the top of the tree are 21° 19' and 16°20'.
1) Convert the angles to decimal form:
19' * 1°/60' = 0.32° => 21° 19' = 21.32°
20' * 1°/60' = 0.33° => 16° 20' = 16.33°
2) Deduce the trigonometric ratios from the verbal information.
You can form a triangle with
- horizontal leg x + 65 feet
- elevation angle 16.33°
- vertical leg height of the tree, h
=> trigonometric ratio: tan (16.33) = h /( x + 65) => h = (x+65) * tan(16.33)
You can form a second triangle with:
- horizontal leg x
- elevation angle 21.32°
- vertical leg height of the tree, h
=> trigonometric ratio: tan(21.32) = h / x => h = x * tan(21.32)
Now equal the two expressions for h:
(x+65)*tan(16.33) = x*tan(21.32)
=> x*tan(16.33) + 65*tan(16.33) = x*tan(21.32)
=> x*tan(21.32) - x*tan(16.33) = 65*tan(16.33)
=> x = 65*tan(16.33) / [ tan(21.32) - tan(16.33) ] = 195.73 feet
=> h = 195.73 * tan(21.32) = 76.39 feet.
Answer: 76.39 feet
Answer:
<h2>125 tickets for an adult</h2><h2>and 175 tickets for a student</h2>
Step-by-step explanation:
![a-\text{number of the tickets for an adult}\\s-\text{number of the tickets for a student}\\\\(1)\qquad a+s=300\\(2)\qquad4.5a+3s=1087.5\\------------\\(1)\\a+s=300\qquad\text{subtstitute}\ s\ \text{from both sides}\\a=300-s\\\\\text{Put it to (2):}\\\\4.5(300-s)+3s=1087.5\qquad\text{use distributive property}\\\\(4.5)(300)+(4.5)(-s)+3s=1087.5\\\\1350-4.5s+3s=1087.5\qquad\text{subtract 1350 from both sides}\\\\-1.5s=-262.5\qquad\text{divide both sides by (-1.5)}\\\\\boxed{s=175}](https://tex.z-dn.net/?f=a-%5Ctext%7Bnumber%20of%20the%20tickets%20for%20an%20adult%7D%5C%5Cs-%5Ctext%7Bnumber%20of%20the%20tickets%20for%20a%20student%7D%5C%5C%5C%5C%281%29%5Cqquad%20a%2Bs%3D300%5C%5C%282%29%5Cqquad4.5a%2B3s%3D1087.5%5C%5C------------%5C%5C%281%29%5C%5Ca%2Bs%3D300%5Cqquad%5Ctext%7Bsubtstitute%7D%5C%20s%5C%20%5Ctext%7Bfrom%20both%20sides%7D%5C%5Ca%3D300-s%5C%5C%5C%5C%5Ctext%7BPut%20it%20to%20%282%29%3A%7D%5C%5C%5C%5C4.5%28300-s%29%2B3s%3D1087.5%5Cqquad%5Ctext%7Buse%20distributive%20property%7D%5C%5C%5C%5C%284.5%29%28300%29%2B%284.5%29%28-s%29%2B3s%3D1087.5%5C%5C%5C%5C1350-4.5s%2B3s%3D1087.5%5Cqquad%5Ctext%7Bsubtract%201350%20from%20both%20sides%7D%5C%5C%5C%5C-1.5s%3D-262.5%5Cqquad%5Ctext%7Bdivide%20both%20sides%20by%20%28-1.5%29%7D%5C%5C%5C%5C%5Cboxed%7Bs%3D175%7D)
![\text{Put the value of}\ s\ \text{to (1):}\\\\a=300-175\\\\\boxed{a=125}](https://tex.z-dn.net/?f=%5Ctext%7BPut%20the%20value%20of%7D%5C%20s%5C%20%5Ctext%7Bto%20%281%29%3A%7D%5C%5C%5C%5Ca%3D300-175%5C%5C%5C%5C%5Cboxed%7Ba%3D125%7D)
Okay so basically 1 + 5 = 180
and if we know 1 = 124 we can assume 5 = 56
and 5 = 4 SOOOO
4 = 56