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nekit [7.7K]
3 years ago
12

I don't this question so I need help with this problem

Mathematics
1 answer:
sveta [45]3 years ago
4 0
So first divide 7,500 by 150 and you will get 50.Next,do 17X50 which will give you 850.The answer is 850 Gold beads.Hope that helped.Have a happy new year
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Which of the following describes the angle of rotation of a counterclockwise rotation?
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polet [3.4K]

Answer:

A

Step-by-step explanation:

2(1)+ 1(2)+ 2(3)+2(4)+ 3(5)/ 10

= 2+2+6+8+15/10

= 33/10

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Answer:

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katrin2010 [14]

Answer:

1/ x = 22.5°

2/ x = 60°

Step-by-step explanation:

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2 years ago
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Question:
prohojiy [21]
Let f(x) = p(x)/q(x), where p and q are polynomials and reduced to lowest terms. (If p and q have a common factor, then they contribute removable discontinuities ('holes').) 
Write this in cases: 
(i) If deg p(x) ≤ deg q(x), then f(x) is a proper rational function, and lim(x→ ±∞) f(x) = constant. 
If deg p(x) < deg q(x), then these limits equal 0, thus yielding the horizontal asymptote y = 0. 
If deg p(x) = deg q(x), then these limits equal a/b, where a and b are the leading coefficients of p(x) and q(x), respectively. Hence, we have the horizontal asymptote y = a/b. 
Note that there are no obliques asymptotes in this case. ------------- (ii) If deg p(x) > deg q(x), then f(x) is an improper rational function. 
By long division, we can write f(x) = g(x) + r(x)/q(x), where g(x) and r(x) are polynomials and deg r(x) < deg q(x). 
As in (i), note that lim(x→ ±∞) [f(x) - g(x)] = lim(x→ ±∞) r(x)/q(x) = 0. Hence, y = g(x) is an asymptote. (In particular, if deg g(x) = 1, then this is an oblique asymptote.) 
This time, note that there are no horizontal asymptotes. ------------------ In summary, the degrees of p(x) and q(x) control which kind of asymptote we have. 
I hope this helps!
4 0
3 years ago
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