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3 years ago

Select the graph that would represent the best presentation of the solution set. | y + 2 | > 6

Mathematics

1 answer:

bija089 [108]3 years ago

5 0

I believe it’s 9y because u add
6+2 = 9 and you add the Y at the end so it will be nine why

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Solve the right triangle. round your answers to the nearest tenth. help.

hammer [34]

Answer:

19.2

Step-by-step explanation:

Cosine rule :

$\sqrt{a^{2} +b^{2} ﹣2abcos(angle ) }$

c will always be the hypotenuse.

a and b can be any if the opposite or the adjacent.

${15}^{2} + 12^{2} - 2 \times 15 \times 12 \times \cos(90) = 369$

\sqrt{369}=19.20937...

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3 years ago

Should politics discuss whether women can get abortion??? Why or why not????

Doss [256]

Answer:

yes

Step-by-step explanation:

i am young but I think they should because they discuss if it's legal to abort a human life or not. there's lots of debates on why it's good or bad

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3 years ago

Read 2 more answers

A circle measures 12 feet in diameter What's its area to the nearest foot?

melomori [17]

Answer:

113.1ft²

Step-by-step explanation:

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3 years ago

Which graph shows the solution to the equation below? log Subscript 3 Baseline (x + 3) = log Subscript 0.3 (x minus 1) On a coor

Effectus [21]

Answer:

On a coordinate plane, 2 curves intersect at (1, 1). One curve curves up and to the right from quadrant 3 into quadrant 1. The other curve curves down from quadrant 1 into quadrant 4

Step-by-step explanation:

The first function is given as:

$log_3(x+3)$

The second function is given as:

$log_{0.3}(x-1)$

First we graph both the functions.

We can see that one curves up and to the right from quadrant 3 into quadrant 1. This curve is of $log_3(x+3)$

The other curve curves down from quadrant 1 into quadrant 3

Both curves interest almost at (1,1)

See the graph attached below

Blue line represents first function

Green line represents second function

The solution lies on the Red line.

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3 years ago

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Solve for the roots in the equation below. In your final answer, include each of the necessary steps and calculations. Hint: Use

QveST [7]

$\bf 27\implies 3^3\\\\
i^3\implies i\cdot i\cdot i\implies i^2\cdot i\implies -1\cdot i\implies -i\\\\
-----------------------------\\\\
x^3-27i=0\implies x^3+3^3(-i)=0\implies x^3+(3^3i^3)=0
\\\\\\
x^3+(3i)^3=0\\\\
-----------------------------\\\\
\textit{difference of cubes}
\\ \quad \\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
(a+b)(a^2-ab+b^2)= a^3+b^3\\\\
-----------------------------\\\\$

$\bf (x+3i)[x^2-3ix+(3i)^2]=0\implies 
\begin{cases}
x+3i=0\implies \boxed{x=-3i}\\\\
x^2-3ix+(3i)^2=0
\end{cases}
\\\\\\
\textit{now, for the second one, we'd need the quadratic formula}
\\\\\\
x^2-3ix+(3i)^2=0\implies x^2-3ix+(3^2i^2)=0
$

$\bf x^2-3ix+(-9)=0\implies x^2-3ix-9=0
\\\\\\
\textit{quadratic formula}\\\\
x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}\implies x=\cfrac{3i\pm\sqrt{(-3i)^2-4(1)(-9)}}{2(1)}
\\\\\\
x=\cfrac{3i\pm\sqrt{(-3)^2i^2+36}}{2}\implies x=\cfrac{3i\pm\sqrt{-9+36}}{2}
\\\\\\
x=\cfrac{3i\pm\sqrt{27}}{2}\implies \boxed{x=\cfrac{3i\pm 3\sqrt{3}}{2}}$

7 0

3 years ago