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noname [10]
3 years ago
11

Select the locations on the number line to plot the points _2 _11 and _17

Mathematics
1 answer:
bixtya [17]3 years ago
3 0
17 points after 0, 11 points after 0, and 2 points after 0
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Which type of transformation is shown in the graph?
AysviL [449]
You need to include the actual picture of the graph :)
5 0
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Find the volume of a cylindrical container,whose height is 21cm and diameter is 14cm?
Lena [83]

Answer:

1029\pi

Step-by-step explanation:

Volume= \pi x (radius)^{2} x height = \pi x 7^{2} x 21 = 1029\pi

I hope it helps you!

4 0
3 years ago
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Factorise 16 x²+ 4 y² + 9 z²​
Dominik [7]

Answer:

The expression is not factorable with rational numbers.

Step-by-step explanation:

4 0
3 years ago
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If Neal and Linda had a combined taxable income of $209,150 and filed their federal income tax with the married filing jointly s
Yuki888 [10]

Answer:

correct option is A. $46840.50

Step-by-step explanation:

given data

taxable income = $209,150

solution

we calculate the tax for income is $209,150

The tax of the taxable income over $208,850 but but not over $372950 is

tax of the taxable income over $208,850 =  $47741.50  plus 33% of the amount over $208850

tax = $47741.50 + 33% of ( $209,150 - $208850  )

tax = $47741.50 + 33% of ( $300)

solve it we get

tax = $46840.5

so correct option is A. $46840.50

5 0
3 years ago
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If the quadratic formula is used to find the solution set of 3x2 + 4x - 2 = 0, what are the solutions?
7nadin3 [17]

Answer:

x=\frac{-2}{3} \pm \frac{\sqrt{10}}{3}

Step-by-step explanation:

Compare ax^2+bx+c to 3x^2+4x-2.

We have a=3,b=4,c=-2.

The quadratic formula is for solving equations of the form ax^2+bx+c=0 and is x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}.

So we are going to plug in our values in that formula to find our solutions,x.

If you want to notice it in parts you can.

Example I might break it into these parts and then put it in:

Part 1: Evaluate b^2-4ac

Part 2: Evaluate -b

Part 3: Evaluate 2a

------Let's do these parts.

Part 1: b^2-4ac=(4)^2-4(3)(-2)=16-12(-2)=16+24=40.

This part 1 is important in determining the kinds of solutions you have. It is called the discriminant.  If it is positive, you have two real solutions.  If it is negative, you have no real solutions (both of the solutions are complex).  If it is 0, you have one real solution.

Part 2: -b=-4 since b=4.

Part 3: 2a=2(3)=6.

Let's plug this in:

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

or in terms of our  parts:

x=\frac{\text{Part 2} \pm \sqrt{\text{Part 1}}}{\text{Part 3}}

x=\frac{-4 \pm \sqrt{40}}{6}

40 itself is not a perfect square but it does contain a factor that is.  That factor is 4.

So we are going to rewrite 40 as 4 \cdot 10.

x=\frac{-4 \pm \sqrt{4 \cdot 10}}{6}

x=\frac{-4 \pm \sqrt{4} \cdot \sqrt{10}}{6}

x=\frac{-4 \pm 2\cdot \sqrt{10}}{6}

I'm going to go ahead and separate the fraction like so:

x=\frac{-4}{6} \pm \frac{2 \cdot \sqrt{10}}{6}

Now I'm going to reduce both fractions:

x=\frac{-2}{3} \pm \frac{1 \cdot \sqrt{10}}{3}

x=\frac{-2}{3} \pm \frac{\sqrt{10}}{3}

6 0
3 years ago
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