Answer: the tuition in 2020 is $502300
Step-by-step explanation:
The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500
The fee in 2018 is the 19th term of the sequence. Therefore,
T19 = $45,4120
n = 19
Therefore,
454120 = 20500 + (19 - 1) d
454120 - 20500 = 19d
18d = 433620
d = 24090
Therefore, an
equation that can be used to find the tuition y for x years after 2000 is
y = 20500 + 24090(x - 1)
Therefore, at 2020,
n = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
4n^4 √3n I believe would be the simplified form.
There are multiple different answers to this question. One of them could be x=0 and y=15. Another is x=12 and y=11. There's no exact correct number
9514 1404 393
Answer:
(c) 108 yd
Step-by-step explanation:
For hypotenuse c and legs a and b, the Pythagorean theorem tells you the relation is ...
c² = a² +b²
Solving for c, we have ...
c = √(a² +b²)
c = √(40² +100²) = √(1600 +10000) = √11600
c ≈ 107.70 . . . . yards
The length of the hypotenuse is about 108 yards.
