6.2:
fraction: .2 = 0.20 = 20/100
fraction: 6 20/100
Word form: six point two
two and five hundredths
fraction: 2 5/100
decimal form 2.05
hope this helps
Piecewise Function is like multiple functions with a speific/given domain in one set, or three in one for easier understanding, perhaps.
To evaluate the function, we have to check which value to evalue and which domain is fit or perfect for the three functions.
Since we want to evaluate x = -8 and x = 4. That means x^2 cannot be used because the given domain is less than -8 and 4. For the cube root of x, the domain is given from -8 to 1. That meand we can substitute x = -8 in the cube root function because the cube root contains -8 in domain but can't substitute x = 4 in since it doesn't contain 4 in domain.
Last is the constant function where x ≥ 1. We can substitute x = 4 because it is contained in domain.
Therefore:
![\large{ \begin{cases} f( - 8 ) = \sqrt[3]{ - 8} \\ f(4) = 3 \end{cases}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20%20%5Csqrt%5B3%5D%7B%20-%208%7D%20%20%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D)
The nth root of a can contain negative number only if n is an odd number.
![\large{ \begin{cases} f( - 8 ) = \sqrt[3]{ - 2 \times - 2 \times - 2} \\ f(4) = 3 \end{cases}} \\ \large{ \begin{cases} f( - 8 ) = - 2\\ f(4) = 3 \end{cases}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20%20%5Csqrt%5B3%5D%7B%20-%202%20%5Ctimes%20-%20%202%20%5Ctimes%20%20%20-%202%7D%20%20%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D%20%5C%5C%20%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20-%202%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D)
Answer
Answer:
if things have similarities that means that have certain things that are the same between them. not always are they the exact same thing
Step-by-step explanation:
Answer:
2nd Option is correct that is ∠T and ∠P.
Step-by-step explanation:
We are given that ΔGET ≅ ΔMAP
We need to find Congruent part from the given options.
Since, we are given the figure of the congruent triangles with marking not any instruction with which vertex is congruent to which vertex.
So, The Given Name of the Congruent triangle.
We deduce that
G ↔ M
E ↔ A
T ↔ P
Using this we get following congruent parts,
GE ≅ MA , GT ≅ MP and ET ≅ AP
∠G ≅ ∠M , ∠E ≅ ∠A and ∠T ≅ ∠P.
Therefore, 2nd Option is correct that is ∠T and ∠P.