If it is only white and silver cars then it would me 75%
The frictional force between the tires and the road prevent the car from skidding off the road due to centripetal force.
If the frictional force is less than the centripetal force, the car will skid when it navigates a circular path.
The diagram below shows that when the car travels at tangential velocity, v, on a circular path with radius, r, the centripetal acceleration of v²/ r acts toward the center of the circle.
The resultant centripetal force is (mv²)/r, which should be balanced by the frictional force of μmg, where μ = coefficient of kinetic friction., and mg is the normal reaction on a car with mass, m.
This principle is applied on racing tracks, where the road is inclined away from the circle to give the car an extra restoring force to overcome the centripetal force.
Answer: The correct answer is Choice C.
For this polynomial to be a perfect square, it would need to be:
(10x + 7)^2
This will ensure that the first terms and the last terms will be 100x^ and 49. However, if you use foil to multiply the factors, you will not get 150x for the center term. Choice C also states that 150x will not be the middle term.
Answer:
- x > -2
- n ≤ -2 or n ≥ 8
Step-by-step explanation:
<h3>1.</h3>
Add 7x-2 to both sides and collect terms.
2x +2 -6x +7x -2 > -4 -7x +7x -2
3x > -6
x > -2 . . . . . . . divide by 3
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<h3>2.</h3>
Solve these one at a time, and form the union of the answers.
1 +7n ≤ 15 . . . .given
7n ≤ 14 . . . . . . subtract 1
n ≤ 2 . . . . . . . divide by 7
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-2n -2 ≤ -18 . . . given
-2n ≤ -16 . . . . . add 2
n ≥ 8 . . . . . . . . divide by -2
The solution is n ≤ -2 or n ≥ 8.
Answer:
Value of x = 7/5
Step-by-step explanation:
Given:
ΔVUW ≅ ΔUST
Find:
Value of x
Computation:
We know that;
ΔVUW ≅ ΔUST
So,
VU = US (By CPCT)
So,
5x + 11 = 18
5x = 7
Value of x = 7/5
