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pochemuha
3 years ago
6

Keith makes 8 dollars for each hour of work. Write an equation to represent his total pay p after working h hours.

Mathematics
1 answer:
Anarel [89]3 years ago
8 0

Answer:

P=8h

Step-by-step explanation:

P is the total amount of dollars that Keith will make, while h is the number of hours he will work for. If you multiply the number of hours he works for and how much he makes in an hour which is 8. You will get the total amount.

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Joey works 20 hours a week. If he works for 10 months continually, how many hours will he have worked? (1 month = 4 weeks)
Tcecarenko [31]
800 because 20*4*10=800 which means he works 80 weeks a month for 10 months
3 0
4 years ago
A particular lawn mower is on sale at two different stores the original price at both stores was $130. Watson’s garden shop is a
matrenka [14]

Answer:

Watson's garden shop has the better deal on the lawn mower.

Hope this helped :)

Step-by-step explanation:

Watson's $130 - 50% = $65

Hartman's $130 - 40% = $78

                  $78 - 15% = About $66

4 0
3 years ago
Read 2 more answers
Simplify the expression ​
miv72 [106K]
6x3= 18 + g =18g (Hope this helped!)
8 0
3 years ago
The value of B is not similar to the value of C.
levacccp [35]
What type of question is this
6 0
3 years ago
find three consecutive odd integers such that the sum of the smallest number and middle number is 27 less than 3 times the large
katrin2010 [14]

A generic odd number can be written as

2k+1,\quad k \in \mathbb{Z}

Since there is an odd number every two numbers, three consecutive odd numbers will be

2k+1,\quad 2k+3,\quad 2k+5

Now let's make up the equations: the sum of the first two is

(2k+1)+(2k+3)

And 27 less than 3 times the largest is

3(2k+5)-27

These two must be the same, so we have

(2k+1)+(2k+3)=3(2k+5)-27 \iff 4k+4 = 6k+30-27 \iff 4k+4=6k+3

Subtracting 4k and 3 from both sides gives

1=2k \iff k=\dfrac{1}{2}

Which means that the problem has no solution.

To confirm this hypothesis, we can observe that, on the left hand side, we have the sum of two odd numbers, which is even

On the right hand side, we have an odd number, multiplied by 3 (still odd), take away 27 (still odd).

So, the left hand side is even, and the right hand side is odd. They can't be the same number.

7 0
4 years ago
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