Answer:
- The radius is r = 3 in,
- The height is h = 4 in
<u>The area of the base:</u>
- A(b) = πr² = π(3²) = 9π in²
<u>The circumference of the base:</u>
<u>The area of the lateral surface:</u>
- A(l) = Ch = 6π(4) = 24π in²
<u>The surface area:</u>
- S = 2A(b) + A(l) = 2*9π + 24π = 42π in²
There wasn't much to go off of but based of the information you've gave me the answer would be 7.68=6.28
To find the perimeter of this blue figure, add together the shown lengths of the six sides.
The three measurements on the top have the LCD 4, so we combine 14 3/4, 4 2/4 and 8 2/4. The sum is 26 7/4, or 27 3/4, or 27.75.
The three measurements on the bottom share the LCD 5, so we can immediately combine them, obtaining 32 8/5, or 33 3/5, or 33.60.
Combining 27.75 and 33.60 results in 61.35, or 61 35/100, or 61 7/20.
The perimeter of the given figure is 61 7/20.
2/ 3 - (3 - 1) * 3 - 1 = -4
Simplify
= 2/-4
which is
= -2/4
Then simplify again
= -1/2