The room-size ranges suggested above for a 4-member family (family with 2 children) and a family with three teenagers are differ
2 answers:
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This is a great question!
To determine the probability with which two sweets are not the same, you would have to subtract the probability with which two sweets are the same from 1. That would only be possible if she chose 2 liquorice sweets, 5 mint sweets and 3 humburgs -
As you can see, the first time you were to choose a Liquorice, there would be 12 out of the 20 sweets present. After taking that out however, there would be respectively 11 Liquorice out of 19 remaining. Apply the same concept to each of the other sweets -
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Calculate the probability of drawing 2 of each, add them together and subtract from one to determine the probability that two sweets will not be the same type of sweet!
<u><em>Thus, the probability should be 111 / 190</em></u>
Answer:
<em>6 days</em>
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Step-by-step explanation:
Let the time taken by Carpenter working alone = days
Then time taken by apprentice alone = Twice as that of taken by Carpenter = 2 days
Time taken working together = 2 days
Work done in one day working together =
Work done in one day by Carpenter working alone =
Work done in one day by apprentice working alone =
Work done in one day by Carpenter working alone + Work done in one day by Carpenter working alone = +
= Work done in one day working together =
Time taken by Carpenter alone to complete the work = 3 days
Time taken by Apprentice alone to complete the work = 3 2= <em>6 days</em>