The dimensions would be 29 by 29.
To maximize area and minimize perimeter, we make the dimensions as close to equilateral as possible.
Dividing the perimeter by the number of sides, we have
116/4 = 29
This means that both length and width can be 29.
Answer:
A) y² - 5y + 1
B) y² - 5y - 4
C) - 5y + 1
D) - 3y² - 4y - 6
Step-by-step explanation:
Let's call P the unkown polynomial and D the difference. In each case, the following must be true:
y² - 5y + 1 - P = D
<em>A)</em>
y² - 5y + 1 - P = 0
y² - 5y + 1 = P
<em>B)</em>
y² - 5y + 1 - P = 5
y² - 5y + 1 - 5 = P
y² - 5y - 4 = P
<em>C)</em>
y² - 5y + 1 - P = y²
y² - 5y + 1 - y² = P
- 5y + 1 = P
<em>D) </em>
y² - 5y + 1 - P = 4y² - y + 7
y² - 5y + 1 - 4y² + y - 7 = P
- 3y² - 4y - 6 = P
Answer:
280in
Step-by-step explanation:
10×6=60
60×2=<u>120</u>
6×10=<u>60</u>
4×4=16
16×2=<u>32</u>
4×6=<u>24</u>
4×4=<u>16</u>
6×6=<u>36</u>
<u>120+60+32+24+16+36=280</u>
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Answer:
16
Step-by-step explanation:
