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vekshin1
4 years ago
6

Please help me with this, I’ve been struggling with it for quite a while.

Mathematics
1 answer:
jolli1 [7]4 years ago
6 0

Answer:

E=10^{19.5961} ergs

Step-by-step explanation:

Given M = 5.2, we can substitute this into the formula and take Log formula into exponential form and solve henceforth.

First, log to exponential >>>>

Log(x)=y\\Means\\10^y=x

Let's put M = 5.2 into the formula and divide by 2/3 to get in log and then change it to exponential form:

M=\frac{2}{3}Log(\frac{E}{10^{11.8}})\\5.2=\frac{2}{3}Log(\frac{E}{10^{11.8}})\\\frac{5.2}{\frac{2}{3}}=Log(\frac{E}{10^{11.8}})\\7.7961=Log(\frac{E}{10^{11.8}})\\10^{7.7961}=\frac{E}{10^{11.8}}\\

Now, we are looking for E, the Energy of the earthquake.

We need to cross multiply and find E. But remember rule of multiplying 2 same bases with different exponents. Its is shown below:

10^{a}*10^{b}=10^{a+b}

So we have:

10^{7.7961}=\frac{E}{10^{11.8}}\\10^{7.7961}*10^{11.8}=E\\10^{7.7961+11.8}=E\\E=10^{19.5961}

So, Energy is 10^{19.5961} ergs

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