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algol13
3 years ago
13

Asap pls I desperately need it​

Mathematics
2 answers:
grigory [225]3 years ago
8 0

Answer: At [3 pi / 2 ] K, where K = a random constant Sin Theta = -1

Step-by-step explanation:

xz_007 [3.2K]3 years ago
4 0
It would be 1 fjjffjdj fifth because the ending would replace the 8
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Which numbers are greater than 0.7? 0.37, 0.9, 0.08, 0.69, 0.71
nikitadnepr [17]
Hello!

The following numbers are greater than 0.7:

0.9 and 0.71.
5 0
3 years ago
Simplify 4n5 + 3.5n5 + (-2.1n5).<br><br> 4.4 n5<br> 5.4 n5<br> 20 n5<br> 6.4 n5
ella [17]

Answer:

4 {n}^{5}  + 3.5 {n}^{5}  + ( - 2.1 {n}^{5} )

first create a bracket:

= ( {4n}^{5}  + 3.5 {n}^{5} ) + ( - 2.1 {n}^{5} )

then solve the first bracket:

=  {7.5 {n}^{5} } + ( - 2.1 {n}^{5} )

then open the remaining bracket:

=  {7.5n}^{5}  -  {2.1n}^{5}

carryout the subtraction operation:

= (7.5 - 2.1) {n}^{5}  \\ { \boxed{ =  {5.4n}^{5} }}

7 0
3 years ago
PLEASE HELP <br> 100!!! POINTS
faust18 [17]

Answer:

Most Unlikely:  Less than 5

Likely:  2-digit number

Unlikely:  Multiple of 3

Equally Likely:  Odd

Most Likely:  Greater than 10

Step-by-step explanation:

there are 6x5, or 30 outcomes

Less than 5 has 1 outcome - spinner and dice both are one

Odd has 15 outcomes

Multiple of 3 has 8 outcomes:  1+5, 2+1, 2+7, 2+12, 3+12, 4+5, 5+7, 5+10

Two-digits has 12 outcomes

Greater than ten has 16 outcomes

6 0
2 years ago
My question is in the photo
motikmotik

Answer:

all the answers are there in safari can  just check it

Step-by-step explanation

6 0
3 years ago
PLEASE HELP ME
denis23 [38]

Answer:

(1) The possible outcomes are: X = {0, 1, 2, 3}.

(2) The number of times should Hartley spin a difference of 1 is 36.

(3) The number of times should Hartley spin a difference of 0 is 24.

Step-by-step explanation:

The number of sections on the spinner is 4 labelled as {1, 2, 3, 4}.

The total number of spins for each of the spinner is, <em>n</em> = 96.

(1)

The sample space of spinning both the spinners together are:

S = {(1, 1), (1, 2), (1, 3), (1, 4)

      (2, 1), (2, 2), (2, 3), (2, 4)

      (3, 1), (3, 2), (3, 3), (3, 4)

      (4, 1), (4, 2), (4, 3), (4, 4)}

Total = 16.

The possible outcomes are:

X = {0, 1, 2, 3}.

(2)

The sample space with the difference 1 are:

S₁ = {(1, 2), (2, 1), (2, 3), (3, 2), (3, 4), (4, 3)}

n (S₁) = 6

The probability of the difference 1 is:

P(\text{Diff}=1)=\frac{n(S_{1})}{N}=\frac{6}{16}=\frac{3}{8}

The spinners were spinner 96 times.

The expected number of times would Hartley spin a difference of 1 is:

E(\text{Diff}=1)=P(\text{Diff}=1)\times n\\\\=\frac{3}{8}\times 96\\\\=36

Thus, the number of times should Hartley spin a difference of 1 is 36.

(3)

The sample space with the difference 0 are:

S₂ = {(1, 1), (2, 2), (3, 3), (4, 4)}

n (S₂) = 4

The probability of the difference 0 is:

P(\text{Diff}=0)=\frac{n(S_{2})}{N}=\frac{4}{16}=\frac{1}{4}

The spinners were spinner 96 times.

The expected number of times would Hartley spin a difference of 0 is:

E(\text{Diff}=0)=P(\text{Diff}=0)\times n\\\\=\frac{1}{4}\times 96\\\\=24

Thus, the number of times should Hartley spin a difference of 0 is 24.

4 0
3 years ago
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