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3 years ago

-7-(-6)-(-5) using keep, flip, change method

Mathematics

2 answers:

yKpoI14uk [10]3 years ago

8 0

The answer for this one is -8

Vlad [161]3 years ago

7 0

-7-(-6)-(-5)
+6+5
^
+11 -7 = +4 is the answer
The negative 6 and 5 turn into a positive because there is a double negative so you add both and then subtract -7

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Answer:

Step-by-step explanation:

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snow_tiger [21]

Answer: I believe it would be $600

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4 years ago

A cylidrical container of height 28cm and diameter of 18cm is with water. The water is then poured into another container with a

MAVERICK [17]

Answer:

23.9894949495cm is the depth of the container.

Step-by-step explanation:

Cylindrical container:

height: 28

radius: 9 (or 18/2)

pi * 9² = 254.4690049408

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I assume that the container with rectangular base is precisely full when tou pour the water into it.

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4 years ago

Evaluate the expression <br><br><br><br>please HELP

mamaluj [8]

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3 years ago

Find a nonzero vector orthogonal to the plane through the points: ????=(0,0,1), ????=(−2,3,4), ????=(−2,2,0).

ser-zykov [4K]

Answer:

The nonzero vector orthogonal to the plane is <-9,-8,2>.

Step-by-step explanation:

Consider the given points are P=(0,0,1), Q=(−2,3,4), R=(−2,2,0).

$\overrightarrow {PQ}==$

$\overrightarrow {PR}==$

The nonzero vector orthogonal to the plane through the points P,Q, and R is

$\overrightarrow n=\overrightarrow {PQ}\times \overrightarrow {PR}$

$\overrightarrow n=\det \begin{pmatrix}i&j&k\\ \:\:\:\:\:-2&3&3\\ \:\:\:\:\:-2&2&-1\end{pmatrix}$

Expand along row 1.

$\overrightarrow n=i\det \begin{pmatrix}3&3\\ 2&-1\end{pmatrix}-j\det \begin{pmatrix}-2&3\\ -2&-1\end{pmatrix}+k\det \begin{pmatrix}-2&3\\ -2&2\end{pmatrix}$

$\overrightarrow n=i(-9)-j(8)+k(2)$

$\overrightarrow n=-9i-8j+2k$

$\overrightarrow n=$

Therefore, the nonzero vector orthogonal to the plane is <-9,-8,2>.

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3 years ago