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GREYUIT [131]
3 years ago
10

Make d the subject of this formula c=7d

Mathematics
2 answers:
Arlecino [84]3 years ago
5 0
Divide both sides by 7 to get c/7=d
ludmilkaskok [199]3 years ago
4 0
Isolate the d

divide 7 from both sides

c/7 = 7d/7

c/7 = d

d = c/7 is your answer

hope this helps
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The point (–3, –5) is on the graph of a function. Which equation must be true regarding the function?
lisov135 [29]
<span>So the question is what does the point (-3, -5) correspond to on the graph of the function. If we have a point on a graph in the Cartesian coordinate system then that point consists of coordinates (x, y). In other words, y=f(x) and x so (x, f(x)) where x is a x-coordinate and y=f(x) is y-coordinate. So if we have a point (-3, -5) the corresponding coordinates are x=-3 and y=f(x)=-5. So it must be true that y=f(-3)=-5. So the correct answer is a. f(-3)=-5.</span>
6 0
3 years ago
Read 2 more answers
Please help ive been stuck on this question.
RUDIKE [14]

The value of the expression 8 / m - 11 / 3m is  13 / 3m

<h3 /><h3>How to simplify an expression?</h3>

8 / m - 11 / 3m

Therefore,

8 / m - 11 / 3m

The factor of the denominator is 3m

Therefore,

8 / m - 11 / 3m = 3(8) - 11/ 3m

3(8) - 11/ 3m = 24 - 11 / 3m

24 - 11 / 3m = 13 / 3m

learn more on fraction here: brainly.com/question/24161414

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7 0
2 years ago
The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 43 o
xeze [42]

Answer:

a) 95% of the widget weights lie between 29 and 57 ounces.

b) What percentage of the widget weights lie between 12 and 57 ounces? about 97.5%

c) What percentage of the widget weights lie above 30? about 97.5%

Step-by-step explanation:

The empirical rule for a mean of 43 and a standard deviation of 7 is shown below.  

a) 29 represents two standard deviations below the mean, and 57 represents two standard deviations above the mean, so, 95% of the widget weights lie between 29 and 57 ounces.  

b) 22 represents three standard deviations below the mean, and the percentage of the widget weights below 22 is only 0.15%. We can say that the percentage of widget weights below 12 is about 0. Equivalently we can say that the percentage of widget weights between 12 an 43 is about 50% and the percentage of widget weights between 43 and 57 is 47.5%. Therefore, the percentage of the widget weights that lie between 12 and 57 ounces is about 97.5%

c) The percentage of widget weights that lie above 29 is 47.5% + 50% = 97.5%. We can consider that the percentage of the widget weights that lie above 30 is about 97.5%

3 0
3 years ago
I the revenue for the week is $2000, and labor cost consists of two workers earning $8 per hour who work 40 hours each, what is
MA_775_DIABLO [31]

Revenue = $2000


Labour cost = 40 x 8 = $320


Percentage = 320/2000 x 100 = 16%


Answer: 16%

4 0
3 years ago
Item 31 Simplify (3x3y0x−2)4⋅(y2x−45xy−8)3. Write your answer using only positive exponents. Evaluate any numerical powers. The
madam [21]

Answer:

1032xy + 72

Step-by-step explanation:

(3x3y0x-2)4(y2x-45xy-8)3=

(0-2)×4(2xy-45xy-3)×3=

-2×4(2xy-45xy-3)×3=

-2×4(-43xy-3)×3=

-24(-43xy-3)

1032xy+72

8 0
3 years ago
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