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Harlamova29_29 [7]

3 years ago

7

Please show work and thank you

1 answer:

shepuryov [24]3 years ago

6 0

150*10%=15
15*3=45

150+45=195

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Amanda's school is due west of her house and due south of her friend Shereen's house. The distance between the school and Sheree

Blizzard [7]

The Amanda's house is 6.7 km far from her school.

<u>Step-by-step explanation:</u>

From the given information,

The Amanda's school is due west of her house forms the base.
The school is due south of the Shereen's house forms the height.
The straight-line distance between Amanda's house and Shereen's house forms the hypotenuse.

Therefore, It can be determined that it forms the right angle triangle.

It is given that,

The distance between the school and Shereen's house is 2 kilometers.

That is, the height of the triangle = 2 km

The straight-line distance between Amanda's house and Shereen's house is 7 kilometers.

That is, the hypotenuse of the triangle = 7 km

Now, the distance between the Amanda's house and her school is the base of the triangle.

<u>To find the base :</u>

Base = $\sqrt{(hypotenuse)^{2}-(height)^{2} }$

⇒ $\sqrt{(7)^{2} -(2)^{2} }$

⇒ $\sqrt{49-4}$

⇒ $\sqrt{45}$

⇒ 6.7 km

Therefore, the Amanda's house is 6.7 km far from her school.

3 0

3 years ago

Solve. 3 is less than y minus 2

vovangra [49]

Answer:

$\bold{3 < (y - 2)} \\ \bold{y > 3 + 2} \\\bold{ y > 5}$

hope helpful~

5 0

2 years ago

Read 2 more answers

Does the point (-4, 3) fall on the graph of this line? How do you know? Show your work. ( 2 points) PLEASE HELP ILL MARK BRAINLI

Elanso [62]

Answer:

Step-by-step explanation:

Since we know the line goes through points $(8,9)$ and $(2,4)$ , we can construct a line in slope-intercept form

$y = mx + b$

where $m$ is the slope and $b$ is the Y-intercept.

The slope can be found using the two points provided:

$\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

$\frac{9 - 4}{8 - 2}$

$\frac{5}{6}$

The line is now represented as

$y = \frac{5}{6}x + b$

To solve for $b$ , we can plug in one of the two points:

$y = \frac{5}{6}x + b$

$(9) = \frac{5}{6}(8) + b$

$4 = \frac{20}{3} + b$

$b = \frac{-8}{3}$

We know have our line:

$y = \frac{5}{6}x - \frac{8}{3}$

To determine if the point $(-4, 3)$ falls on this line, we just plug the numbers into the equation and see if it holds true:

$y = \frac{5}{6}x - \frac{8}{3}$

$(3) = \frac{5}{6}(-4) - \frac{8}{3}$

$3 = \frac{-10}{3} - \frac{8}{3}$

$3 = \frac{-18}{3}$

$3 = -6$

This does not hold true, so the point is not on the line.

3 0

3 years ago

F(x)8x^2 find its inverse

olya-2409 [2.1K]

Answer:

$f^{-1}(x)=\frac{1}{2}\sqrt{\frac{x}{2}}$

Step-by-step explanation:

Given:

The function is given as;

$f(x)=8x^2$

In order to find the inverse, the steps to be followed are:

Step 1: Replace $f(x)$ by $y$ . This gives,

$y=8x^2$

Step 2: Switch 'y' by 'x' and 'x' by 'y'. This gives,

$x=8y^2$

Step 3: Solve for 'y'.

Dividing both sides by 8, we get:

$\frac{x}{8}=\frac{8y^2}{8}$

$\frac{x}{8}=y^2$ or

$y^2=\frac{x}{8}$

Taking square root on both sides, we get:

$\sqrt{y^2}=\sqrt{\frac{x}{8}}$

$y=\frac{1}{2}\sqrt{\frac{x}{2}}$

Now, we replace 'y' by $f^{-1}(x)$ .

Therefore, the inverse of the given function is:

$f^{-1}(x)=\frac{1}{2}\sqrt{\frac{x}{2}}$

3 0

3 years ago

What is the distributive property of 0.4(0.3m+0.6n

svlad2 [7]

Answer:

Distributive property for the given expression is

$0.4(0.3m+0.6n)=0.12m+0.24n$

Step-by-step explanation:

Distributive property:

The distributive property lets you multiply a sum by multiplying each addend separately and then add the products.

$A(B+C)=A\times B + A\times C$

For example 2(x+y)=2x+2y

Therefore,

$0.4(0.3m+0.6n)=0.4\times 0.3m+0.4\times 0.6n=0.12m+0.24n$

Therefore,

$0.4(0.3m+0.6n)=0.12m+0.24n$

5 0

4 years ago