131 3/4 ⇒ 115 5/8 ⇒ 5 2/3
Subtract 131 3/4 by 115 5/8.
131 3/4 ⇒ 131 6/8
131 6/8 - 115 5/8 = 16 1/8
Now add 16 1/8 + 5 2/3 and this will give you how much weight she lost in all.
16 1/8 ⇒ 16 3/24
5 2/3 ⇒ 5 16/24
16 3/24 + 5 16/24 = 21 19/24
Felice lost 21 19/24 pounds in all.
I do believethe answer would e 4960 stickers is what Menon would have.
Supposing a normal distribution, we find that:
The diameter of the smallest tree that is an outlier is of 16.36 inches.
--------------------------------
We suppose that tree diameters are normally distributed with <u>mean 8.8 inches and standard deviation 2.8 inches.</u>
<u />
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- The Z-score measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.<u>
</u>
<u />
In this problem:
- Mean of 8.8 inches, thus
. - Standard deviation of 2.8 inches, thus
.
<u />
The interquartile range(IQR) is the difference between the 75th and the 25th percentile.
<u />
25th percentile:
- X when Z has a p-value of 0.25, so X when Z = -0.675.




75th percentile:
- X when Z has a p-value of 0.75, so X when Z = 0.675.




The IQR is:

What is the diameter, in inches, of the smallest tree that is an outlier?
- The diameter is <u>1.5IQR above the 75th percentile</u>, thus:

The diameter of the smallest tree that is an outlier is of 16.36 inches.
<u />
A similar problem is given at brainly.com/question/15683591
Answer:
Vertical movement: Move up 3 units
or
Horizontal movement: Move left 3 units
Step-by-step explanation:
If your parent equation is
and your child equation is
, then it has vertically moved up 3 units.
If your parent equation is
and your child equation is
, then it has moved horizontally left 3 units.
where are the options am not seeing them