Question

PLEASE HELP ME!

Answer 1

Given the linear equation, -x + 2y = 6, we can set y = 0 to find the x-intercept.

The x-intercept is the point on the graph where it crosses the x-axis, and has coordinates of (a, 0), where a = x-intercept.


-x + 2y = 6
-x + 2(0) = 6
- x + 0 = 6
-x = 6

Divide both sides by -1 to isolate x:
-x/-1 = 6/-1

x = -6

Therefore, the x-intercept is (-6, 0), where its x-coordinate, a = -6.

Next, in order to solve for the y-intercept, set x = 0.

The y-intercept is the point on the graph where it crosses the y-axis, and has coordinates of (0, b), where b = y-intercept.

-x + 2y = 6
-(0) + 2y = 6
0 + 2y = 6
2y = 6

Divide both sides by 2 to isolate y:

2y/2 = 6/2

y = 3

Therefore, the y-intercept is (0, 3), where its y-coordinate, b = 3.