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sp2606 [1]
3 years ago
12

A professor gives his students 9 essay questions to prepare for an exam. Only 3 of the questions will actually appear on the exa

m. How many different exams are possible?
Mathematics
1 answer:
Talja [164]3 years ago
4 0

Answer: 84

Step-by-step explanation:

The total number of the questions is 9

Possible question is 3

This is combination

Therefore n=9 and r=3

Combination formula=n! / ((n-r)! r!)

9C3=9! /((9-3)! 3!)

=362880 /(6! 3!)

=362880/4320

=84

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If the endpoints of the diameter of a circle are (8, 6) and (2,0), what is the standard form equation of the circle?
zvonat [6]

Answer:

It is C.

Step-by-step explanation:

The centre of the circle is at the midpoint of The diameter = (8+2)/2, (6+0)/2 = (5,3) so the left side of the equation is (x-5)^2+(Y-3)^2. Now we need to work out the radius:

The diameter = square root(8-2)^2+6^2) = square root of 72 = 6sqrt2.

So the radius = 3sqrt2 and r^2=18.

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3 years ago
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You can do 109 divide by 100 then multiply it by the percent you need 109/100= 1.09*57=62.13
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I need help I put 30 points for whoever helps me
artcher [175]

Answer:

y=-x+1

Step-by-step explanation:

Slope can be represented as rise over run (change y-values over change in x-values). Since the y-value is changing by -2 every time the x-value is changing by 2, the slope of the line must be \frac{-2}{2}=-1.

In slope-intercept form y=mx+b, m represents the slope of the line, b represents the y-intercept, and (x, y) represent the coordinates of any point the line passes through.

To find b, substitute m=-1 and any point the line passes through.

Using (1, 0) from the table:

0=-1(1)+b,\\0=-1+b,\\b=1

Thus, the equation of this line is \boxed{y=-x+1}

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3 years ago
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Is the value of the fraction 7−2y/6 greater than the value of the fraction 3y−7/12 ?
Sveta_85 [38]

Complete Question:

Is the value of the fraction 7−2y/6 greater than the value of the fraction 3y−7/12 ?  For what values?(Make sure to use an inequality)

Answer:

y < 3

Step-by-step explanation:

The given two fractions are:

\frac{7-2y}{6} and \frac{3y-7}{12}

We have to tell for which range of values is the value of first fraction larger than the second fraction. This can be done by setting up an inequality as shown:

\frac{7-2y}{6} >\frac{3y-7}{12}

The range of y which will satisfy this inequality will result in first fraction of larger value as compared to the second fraction.

Multiplying both sides of inequality by 12, we get:

12 \times \frac{7-2y}{6} > 12 \times \frac{3y-7}{12} \\\\  2(7-2y)>3y-7\\\\ 14-4y>3y-7\\\\ 14+7>3y+4y\\\\ 21>7y\\\\ 3>y\\\\ y

This means, for y lesser than 3, the value of first fraction is larger than the second one.

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3 years ago
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