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Svet_ta [14]
3 years ago
11

How do I do these? My math teacher didn’t explain it very well

Mathematics
1 answer:
Elden [556K]3 years ago
3 0

Answer:WFG=116

Step-by-step explanation:

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39. You need to rent a car for a trip. Wrecko'mend charges $. 10 a mile plus a $30 flat fee. Rent a Wreck
Wewaii [24]

i think this is a systems of equations

putting this on a graph we have to equations:

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it has to be more than or equal to 3 miles i think for wreckomend

5 0
3 years ago
the coordinates of a line segment are (1,6) and (11, -4). what is the length of the line segment? round your answer to the neare
ddd [48]
The length of the line segment AB where A(x_A;\ y_A) and B(x_B;\ y_B)

|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}

We have: A(1;\ 6);\ B(11;-4)

subtitute

|AB|=\sqrt{(1-11)^2+(6-(-4))^2}=\sqrt{(-10)^2+10^2}=\sqrt{100+100}\\\\=\sqrt{100\cdot2}=\sqrt{100}\cdot\sqrt2=10\sqrt2\approx14.1

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3 0
3 years ago
A small regional carrier accepted 23 reservations for a particular flight with 20 seats. 14 reservations went to regular custome
MrRissso [65]

Answer:

- The probability that overbooking occurs means that all 8 non-regular customers arrived for the flight. Each of them has a 56% probability of arriving and they arrive independently so we get that  

P(8 arrive) = (0.56)^8 = 0.00967

- Let's do part c before part b. For this, we want an exact booking, which means that exactly 7 of the 8 non-regular customers arrive for the flight. Suppose we align these 8 people in a row. Take the scenario that the 1st person didn't arrive and the remaining 7 did. That odds of that happening would be (1-.56)*(.56)^7.

Now take the scenario that the second person didn't arrive and the remaining 7 did. The odds would be  

(0.56)(1-0.56)(0.56)^6 = (1-.56)*(.56)^7. You can run through every scenario that way and see that each time the odds are the same. There are a total of 8 different scenarios since we can choose 1 person (the non-arriver) from 8 people in eight different ways (combination).  

So the overall probability of an exact booking would be [(1-.56)*(.56)^7] * 8 = 0.06079

- The probability that the flight has one or more empty seats is the same as the probability that the flight is NOT exactly booked NOR is it overbooked. Formally,  

P(at least 1 empty seat) = 1 - P(-1 or 0 empty seats)  

= 1 - P(overbooked) - P(exactly booked)

= 1 - 0.00967 - 0.06079  

= 0.9295.

Note that, the chance of being both overbooked and exactly booked is zero, so we don't have to worry about that.

Hope that helps!

Have a great day :P

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Step-by-step explanation:

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