Answer:
0, for q ≠ 0 and q ≠ 1
Step-by-step explanation:
Assuming q ≠ 0, you want to find the value of x such that ...
q^x = 1
This is solved using logarithms.
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x·log(q) = log(1) = 0
The zero product rule tells us this will have two solutions:
x = 0
log(q) = 0 ⇒ q = 1
If q is not 0 or 1, then its value is 1 when raised to the 0 power. If q is 1, then its value will be 1 when raised to <em>any</em> power.
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<em>Additional comment</em>
The applicable rule of logarithms is ...
log(a^b) = b·log(a)
Answer:
Discriminant = 20
Step-by-step explanation:
We use formula to find the discriminant.
Discriminant (D) = b^2 - 4ac
The given equation is x^2 - 6x + 4 = 0.
Here the value of a = 1, b = -6 and c = 4.
Plug in the given values in the formula, we get
Discriminant (D) = (-6)^2 - 4*1*4
= 36 - 16
Discriminant = 20
Thank you.
3x + 5 (first plug in 2 for x )
3(2) + 5 =
6 + 5 = 11
Hope this helps . Give brainliest
It is right but what's the full question
Volume is the amount of space that a substance or object occupies, or that is enclosed within a container. It is measured in <span>Volumetric units. </span>
