We have proven that the trigonometric identity [(tan θ)/(1 - cot θ)] + [(cot θ)/(1 - tan θ)] equals 1 + (secθ * cosec θ)
<h3>How to solve Trigonometric Identities?</h3>
We want to prove the trigonometric identity;
[(tan θ)/(1 - cot θ)] + [(cot θ)/(1 - tan θ)] = 1 + sec θ
The left hand side can be expressed as;
[(tan θ)/(1 - (1/tan θ)] + [(1/tan θ)/(1 - tan θ)]
⇒ [tan²θ/(tanθ - 1)] - [1/(tan θ(tanθ - 1)]
Taking the LCM and multiplying gives;
(tan³θ - 1)/(tanθ(tanθ - 1))
This can also be expressed as;
(tan³θ - 1³)/(tanθ(tanθ - 1))
By expansion of algebra this gives;
[(tanθ - 1)(tan²θ + tanθ.1 + 1²)]/[tanθ(tanθ(tanθ - 1))]
Solving Further gives;
(sec²θ + tanθ)/tanθ
⇒ sec²θ * cotθ + 1
⇒ (1/cos²θ * cos θ/sin θ) + 1
⇒ (1/cos θ * 1/sin θ) + 1
⇒ 1 + (secθ * cosec θ)
Read more about Trigonometric Identities at; brainly.com/question/7331447
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Answer:
The 
, 
and 
.
Step-by-step explanation:
The given function is
.... (1)
The general form of sine function is
....(2)
where, |A| is the amplitude, B is period, D is the vertical shift (up or down), and C/B is used to find the phase shift.
On comparing (1) and (2), we get
So,
Therefore , and .
Answer:
x = 11
Step-by-step explanation:
Using Secants ad Segments Theorem we can say;
(x + 7) (7) = (15 + 6) (6)
7x + 49 = (21) (6)
7x + 49 = 126
7x = 77
x = 11
Hope this helps!
True. To solve for y you have to subtract 2 from both sides of the equation.
