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patriot [66]
3 years ago
6

My state's lottery has 30 white balls numbered from 1 through 30 and 20 red balls numbered from 1 through 20. In each lottery dr

awing, 3 of the white balls and 2 of the red balls are drawn. To win, you must match all 3 white balls and both red balls, without regard to the order in which they were drawn. How many possible different combinations may be drawn?
Mathematics
1 answer:
seropon [69]3 years ago
7 0

The three whites:

(30 choose 1) * (29 choose 1) * (28 choose 1) = 30 * 29 * 28


The two reds:

(20 choose 1) * (19 choose 1) = 20 * 19


So, The three whites + two reds = 30 * 29 * 28 + 20 * 19 = 24740

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4x - 7 (2 - x) = 3x + 2
juin [17]

Answer:

x=2

Step-by-step explanation:

4x−7(2−x)=3x+2

4x+(−7)(2)+(−7)(−x)=3x+2(Distribute)

4x+−14+7x=3x+2

(4x+7x)+(−14)=3x+2(Combine Like Terms)

11x+−14=3x+2

11x−14=3x+2

Step 2: Subtract 3x from both sides.

11x−14−3x=3x+2−3x

8x−14=2

Step 3: Add 14 to both sides.

8x−14+14=2+14

8x=16

Step 4: Divide both sides by 8.

x=2

3 0
3 years ago
What is the domain and range of the function?<br> Domain:
ad-work [718]
It depends on the function
8 0
3 years ago
Read 2 more answers
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Lelu [443]

Answer:

13 and 7

Step-by-step explanation:

4 0
3 years ago
WILL GIVE BRAINLIEST DUE NOW!!!!!! Which activities best support development of cardiorespiratory fitness? (5 points) a Push-ups
Ilia_Sergeevich [38]

Answer:

c Aerobics and jumping rope

Thank you and please rate me as brainliest as it will help me to level up

7 0
3 years ago
Two ballpoint pens are selected at random from a box that contains 3 blue pens, 2 red pens, and 3 green pens. If X is the number
Flauer [41]

Answer:

a) f(x,y) =\frac{\binom{3}{x}\binom{2}{y}\binom{3}{2-x-y}}{\binom{8}{2}} ;   x = 0, 1 , 2;  y = 0, 1 , 2; 0 ≤ x+y ≥ 2

b) = \frac{9}{14}

Step-by-step explanation:

joint probability is a function that characterizes the distribution of a random variable. If X and Y be two random variables then the joint probability will be P(X = x, Y=y)

Given Data,

X = The number of blue Pens

Y = The number of red Pens

a)

possible outcomes(X, Y) are (0, 0), (0, 1), (1, 0), (1, 1), (0, 2), (2,0)

Please refer fig. also

total number ways of selecting any 2 pens = \binom{8}{2}= \frac{8!}{2! 6!} =28

f(x,y) = \frac{\binom{3}{x}\binom{2}{y}\binom{3}{2-x-y}}{\binom{8}{2}} ;   x = 0, 1 , 2;  y = 0, 1 , 2; 0 ≤ x+y ≥ 2

b)

P(X,Y)∈A = P(X + Y ≤ 1)

= P(0,0) + P(1,0) + P(0,1)

= \frac{3}{28} + \frac{3}{14} + \frac{9}{28}

= \frac{9}{14}

4 0
3 years ago
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