Answer:
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Step-by-step explanation:
you are a very st*pid f**cking kid your mom prolly doesnt even like u because you are a f**cking mistake smh you are a very d*mb*ss kid ngl
Answer:
The correct option is;
C. 52.2 × 4.4 × 2 + 47.8 × 4.4 × 2
Step-by-step explanation:
The area of the square frame is the area of the inner square subtracted from the area of the outer square
Which gives;
52.2² - 47.8² = 440
Therefore;
Option A. 52.2² - 47.8² is a correct way of finding the area of the square frame
Option B. 2 × ((52.2×2.2) + (47.8×2.2)) = 440, is a correct way of finding the area of the square frame
Option C. 52.2 × 4.4 × 2 + 47.8 × 4.4 × 2 = 880, is not a correct way of finding the area of the square frame
The error is the thickness is 2.2 not 4.4
Option D. 100×(52.2 - 47.8) = (52.2 + 47.8) × (52.2 - 47.8) = 52.2² - 47.8² = 440, is a correct way of finding the area of the square frame
Add all the number the points are on and you get your answer
Answer:
Step-by-step explanation:
Correlation measures the strength of the linear relationship between two variables.
A linear relationship exists between two variables if one variable increases as the other increases or decreases.
Use the formula for correlation coefficient to determine the strength of the relationship.
Correlation coefficient, r is equal to the sum of squares of xy divided by the product of the square root of the sum of squares of xx and xy.
The sample correlation coefficient r measures the strength of the linear relationship and has the following properties:
-1≤r≤1; the closer the value is to −1 or 1, the stronger the linear relationship
– If r is negative, this indicates that as one variable is increasing, the other is decreasing
– If r is positive, this indicates that both variables are increasing or both variables are decreasing
If r = 0, then there is no linear relationship between the two variables
When r is the weight of the rabbit:
13r = 104
/13 /13
r = 8
Now, subtract:
104
<span>- 8
</span>= <span>96
</span>Dylan's dog weighs 96 pounds.
Hope this helps!
