Round 6.09933418366 to 4 decimal places

I need a bit of help on BOTH of these. Anyone?

Leona [35]

Answer:

5) "C"

6) DOMAIN: {-3,-1,2,4,6}

RANGE: {4,1,2,-2,6}

Step-by-step explanation:

3 0

2 years ago

N+5/16=-1 Solve for n I will reward Brainliest

Wittaler [7]

Answer:

Step-by-step explanation:

+

5

1

6

=

−

1

n+\frac{5}{16}=-1

n+165=−1

Solve

1

Subtract

5

1

6

\frac{5}{16}

165

from both sides of the equation

+

5

1

6

=

−

1

n+\frac{5}{16}=-1

n+165=−1

+

5

1

6

−

5

1

6

=

−

1

−

5

1

6

n+\frac{5}{16}{\color{#c92786}{-\frac{5}{16}}}=-1{\color{#c92786}{-\frac{5}{16}}}

n+165−165=−1−165

2

Simplify

Solution

=

−

2

1

3 0

3 years ago

Find the compound interest on Rs. 2000 for one year at the rate of '20%' per annum. If theinterest compounded quarterly.

trasher [3.6K]

Given:

Principal = Rs. 2000

Rate of interest = 20% p.a. compounded quarterly.

Time = 1 year

To find:

The compound interest.

Solution:

Formula for amount:

$A=P\left (1+\dfrac{r}{n}\right)^{nt}$

where,

P = Principal

r = Rate of interest

t= Time

n = number of times interest compounded in an year.

Putting P=2000, r=0.2, n=4 and t=1, we get

$A=2000\left (1+\dfrac{0.2}{4}\right)^{4(1)}$

$A=2000\left (1.05\right)^{4}$

$A=2000\left (1.21550625\right)$

$A=2431.0125$

Now, the compound interest is

$C.I.=A-P$

$C.I.=2431.0125-2000$

$C.I.=431.0125$

Therefore, the compound interest is Rs 431.0125.

3 0

3 years ago

Plus help me its really simple ill give you the brainiest

kobusy [5.1K]

Answer:

Whole Numbers

Step-by-step explanation:

Whole numbers is the only set of numbers in the following choices that don't include negative numbers (only positive integers and zero). Therefore, since -7 is negative, it doesn't belong to whole numbers!

3 0

3 years ago

Pls help me solve this

sammy [17]

Answer:

4 kg of sugar would contain $1.2 \times 10^9$ crystals.

Step-by-step explanation:

Given that 3kg of sugar contains 9 × 10⁸ crystals, let "x" represent the number of sugar crystals 4kg of sugar would contain.

Thus, set up a proportion as follows:

3 kg : 9 × 10⁸ = 4 kg : x

$\frac{3}{9 \times 10^8} = \frac{4}{x}$

Solve for x. Cross multiply.

$3 \times x = 9 \times 10^8 \times 4$

$3x = 36 \times 10^8$

$3x = 3.6 \times 10^9$

Divide both sides by 3

$\frac{3x}{3} = \frac{3.6 \times 10^9}{3}$

$x = 1.2 \times 10^9$

4 kg of sugar would contain $1.2 \times 10^9$ crystals.

5 0

3 years ago