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allsm [11]
3 years ago
11

What is 180% as a decimal

Mathematics
2 answers:
bazaltina [42]3 years ago
7 0

Answer:

1.80 this is the correct answer

yulyashka [42]3 years ago
4 0

\huge\text{Hey there!}

\large\text{What is \underline{1\bf{80\% as a decimal?}}}

\large\text{GUIDE for UNDERSTANDING percentages}\downarrow\\\\\bullet \large\text{ When you hear the word \underline{PERcent} think of its out of 100}\huge\checkmark \\\large\text{(MAINLY over 100)}\\\\\bullet\large\text{ Basic solving:  Get rid of your percentage symbol (\%) and DIVIDE}\\\large\text{your given number by 100}

\large\text{Equation: }\bold{ \180\% = \dfrac{180}{100}}\\\\\large\text{We are going to focus on the }\bold{\dfrac{180}{100}}\large\text{ because it helps us solve for your}\\\large\text{decimal (also known as your result to this question)}\\\\\bold{\dfrac{180}{100}\rightarrow 180\div 100 \rightarrow your \underline{\ answer}}\\\\\bold{= 180\div100 \rightarrow 1.8}\\\\\large\text{180\% = \bf{1.8}}\\\\\boxed{\boxed{\large\text{Therefore, your answer is: \bf{1.8}}}}\huge\checkmark

\textsf{Good luck on your assignment and enjoy day!}

~\frak{Amphitrite1040:)}

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For the Parabolay = (x – 7)2 – 3. the equation for the Line Of Symmetry is
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A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we
weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

        P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample mean weighing of specimen = \frac{3.412+3.416+3.414}{3} = 3.414 g

            \sigma = population standard deviation = 0.001 g

            n = sample of specimen = 3

            \mu = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population​ mean, \mu is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5% level

                                                            of significance are -2.5758 & 2.5758}

P(-2.5758 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X - \mu} < 2.5758 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

P( \bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } } ]

                                             = [ 3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } } , 3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } } ]

                                             = [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0
3 years ago
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