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3 years ago

What is 180% as a decimal

Mathematics

2 answers:

bazaltina [42]3 years ago

7 0

Answer:

1.80 this is the correct answer

yulyashka [42]3 years ago

4 0

$\huge\text{Hey there!}$

$\large\text{What is \underline{1\bf{80\% as a decimal?}}}$

$\large\text{GUIDE for UNDERSTANDING percentages}\downarrow\\\\\bullet \large\text{ When you hear the word \underline{PERcent} think of its out of 100}\huge\checkmark \\\large\text{(MAINLY over 100)}\\\\\bullet\large\text{ Basic solving: Get rid of your percentage symbol (\%) and DIVIDE}\\\large\text{your given number by 100}$

$\large\text{Equation: }\bold{ \180\% = \dfrac{180}{100}}\\\\\large\text{We are going to focus on the }\bold{\dfrac{180}{100}}\large\text{ because it helps us solve for your}\\\large\text{decimal (also known as your result to this question)}\\\\\bold{\dfrac{180}{100}\rightarrow 180\div 100 \rightarrow your \underline{\ answer}}\\\\\bold{= 180\div100 \rightarrow 1.8}\\\\\large\text{180\% = \bf{1.8}}\\\\\boxed{\boxed{\large\text{Therefore, your answer is: \bf{1.8}}}}\huge\checkmark$

$\textsf{Good luck on your assignment and enjoy day!}$

~ $\frak{Amphitrite1040:)}$

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EU (European Union) countries report that 46% of their labor force is female. The United Nations wants to determine if the perce

miss Akunina [59]

Answer:

b. We are 95% confident that between 35.5% and 44.3% of the persons in the U.S. labor force is female.

Step-by-step explanation:

1) Data given and notation

n=500 represent the random sample taken

X represent the number of females in the U.S. labor force

$\hat p=0.46$ estimated proportion of females in the U.S. labor force

$\alpha=0.05$ represent the significance level (no given, but is assumed)

z would represent the statistic

p= population proportion of females in the U.S. labor force

2) Confidence interval

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.46 - 1.96 \sqrt{\frac{0.46(1-0.46)}{500}}=0.416$

$0.46 + 2.58 \sqrt{\frac{0.46(1-0.46)}{500}}=0.504$

On this case the calculated interval is not the given , but let's assume that the confidence interval is given by the statment: "United States Department of Labor find that 95% confidence interval for the proportion of females in the U.S. labor force is .357 to .443."

3) Correct interpretation

a. The margin of error for the true percentage of females in the U.S. labor force is between 35.7% and 44.3%.

False the confidence interval not conclude about the margin of error conclude about the true proportion.

b. We are 95% confident that between 35.5% and 44.3% of the persons in the U.S. labor force is female.

True, the statement report the confidence level and the limits for the margin of error.

c. The percentage of females in the U.S. labro force is between 35.7% and 44.3%.

False, The statement is not correct because not reports the confidence level.

d. All sample of size 500 will yield a percentage of females in the U.S. labor force that falls within 35.7% and 44.3%

False the confidence interval is for the population proportion not just for the samples of size 500

e. None of these.

False, we have an option that is true.

8 0

2 years ago

There are 135 people in a sport centre. 77 people use the gym. 62 people use the swimming pool. 65 people use the track. 27 peop

umka21 [38]

Answer:

The correct answer is $\frac{2}{9}$ .

Step-by-step explanation:

There are 135 people in a sport centre.

Let the experiment be to pick a person from the sport centre who only uses exactly one of the facilities.

Total number of possible outcomes = 135

For the gym:

77 people use the gym.

27 people use the gym and the pool.

31 people use the gym and the track.

4 people use all three facilities.

Total number of people using only the gym are 77 - ( 27 + 31 + 4) = 15

For the swimming pool:

62 people use the swimming pool.

27 people use the gym and the pool.

23 people use the pool and the track.

4 people use all three facilities.

Total number of people using only the swimming pool are 62 - ( 27 + 23 + 4) = 8

For the tracks:

65 people use the track.

23 people use the pool and the track.

31 people use the gym and the track.

4 people use all three facilities.

Total number of people using only the tracks are 65 - ( 23 + 31 + 4) = 7

A person is selected at random.

Favorable outcomes = 7 + 8 + 15 = 30

Probability that the person uses exactly one of the facilities = $\frac{Favorable}{Total}$ = $\frac{30}{135} = \frac{2}{9}$ .

5 0

3 years ago

Fill in the blanks to make the number sentence thue . —/3*11>11. And. 5*——/8<5

ElenaW [278]

Answer:

1)for x > 3 statement (1) is true.

2) for y < 8 statement (2) is true.

Step-by-step explanation:

Given : two sentences.

1) $\frac{x}{3} \times 11>11$

2) $5\times\frac{y}{8}$

We have to find for what values of x and y the statement are true.

Consider

1) $\frac{x}{3} \times 11>11$

We solve for x ,

Divide both side by 11, we get,

$\frac{x}{3}>1$

Now, multiply both side by 3, we get,

$x>3$

Thus, for x > 3 statement (1) is true.

2) $5\times\frac{y}{8}$

Here, we solve for y ,

Divide both side by 5, we get,

$\frac{y}{8}$

Now, multiply both side by 8, we get,

$y$

Thus, for y < 8 statement (2) is true.

4 0

3 years ago

How can you determine the coordinates of the care after a reflection over either axis

MrRa [10]

Well when you reflect over a coordinate it puts the same information on the opposite side, for example:
3,5 reflected now its -3,5

5 0

2 years ago

A $64 item is marked up to $80. Find the percent markup.

swat32

Answer:

The Markup was by 25%

Step-by-step explanation:

The answer is 25% because 25% of 64 is 16

25% * 64 = 16

64 + 16 = 80

So, the price markup was by 25%

Hope this helps! :)

5 0

3 years ago

Read 2 more answers