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2 years ago

7

A cylinder with a diameter of 10 inches and a height of 12 inches. Determine the area of the cross section formed by slicing the

cylinder down the center and perpendicular to the bases.

1 answer:

Colt1911 [192]2 years ago

8 0

Answer:

188.571

if you did directly answer may differ

Step-by-step explanation:

you can see it from the picture above

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A block of ice has a square top and bottom and rectangular sides. At a certain point in

Lilit [14]

Answer:

$\frac{dV}{dt} = 360 \ cm^3/h$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

<u>Geometry</u>

Volume of a Rectangular Prism: V = lwh

<u>Calculus</u>

Derivatives

Derivative Notation

Differentiating with respect to time

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

<u>Step 1: Define</u>

<u /> $l = 30 \ cm\\w = l\\\frac{dl}{dt} = 2 \ cm/h\\h = 20 \ cm\\\frac{dh}{dt} = 3 \ cm/h$ <u />

<u />

<u>Step 2: Differentiate</u>

Rewrite [VRP]: $V = l^2h$
Differentiate [Basic Power Rule]: $\frac{dV}{dt} = 2l\frac{dl}{dt} \frac{dh}{dt}$

<u>Step 3: Solve for Rate</u>

Substitute: $\frac{dV}{dt} = 2(30 \ cm)(2 \ cm/h)(3 \ cm/h)$
Multiply: $\frac{dV}{dt} = 360 \ cm^3/h$

Here this tells us that our volume is decreasing (ice melting) at a rate of 360 cm³ per hour.

3 0

3 years ago

John and Jane are married. The probability that John watches a certain television show is .7. The probability that Jane watches

ikadub [295]

a) The probability that both John and Jane watch the show is 0.12.

b.The probability that Jane watches the show, given that John does is 0.1714.

c)They do watch show independent of each other.

Step-by-step explanation:

Here, as given in the question:

Probability that John watches a certain show = 0.7 ⇒ P(J) = 0.7

Probability that Jane watches a certain show = 0.3 ⇒ P(Je) = 0.3

Probability that John watches a certain show given Jane watches it to

= 0.4 ⇒ P(J/Je) = 0.4

a. ) Here, we need to find the probability of both Jane and John watching a show , P(J∩Je)

Now, by BAYES THEOREM:

$P(J/Je) = \frac{P(J \cap Je)}{P(Je)}$

$\implies 0.4 = \frac{P(J \cap Je)}{0.3} \\\implies P(J \cap Je) = 0.4 \times 0.3 = 0.12$

Hence the probability that both John and Jane watch the show is 0.12.

b.) The probability that Jane watches the show, given that John does is P(J/Je)

By BAYES Theorem:

$P(Je/J) = \frac{P(J \cap Je)}{P(J)}\\\implies P(Je/J) = \frac{0.12}{0.7} = 0.1714$

Hence, the probability that Jane watches the show, given that John does is 0.1714.

c) As we can see P(Jane ∩ John) = 0.12

So, the probability of both of them seeing the show TOGETHER is 0.12.

Hence, they do watch show independent of each other and the probability of doing that is 1.0.12 = 0.88

7 0

3 years ago

HELP! WILL GIVE BRANLIEST!

iogann1982 [59]

10 in each do 10 times 3 then subtract total

6 0

3 years ago

Find the value of y.

True [87]

Answer:

6

Step-by-step explanation:

6 0

3 years ago

In the expression 6x2+y what is the literal coefficient?

PIT_PIT [208]

Answer:

The answer is Y.

Step-by-step explanation:

7 0

3 years ago