Answer:
1.The random variable X can take any value from( 2,- ----,12) in the event of the sample space.
2.The sample space S = [(1, 1), (1, 2),(2, 1), (1, 3), (2, 2),(3, 1), (1, 4),(2, 3),(3, 2),(4, 1), (1, 5),(2, 4), (3, 3),(4, 2),(5, 1),(1, 6), (2, 5),(3, 4),(4, 3),(5, 2), (6, 1), (2, 6),(3, 5), (4, 4), (5, 3), (6, 2),(3, 6), (4, 5), (5, 4), (6, 3),(4, 6) (5, 5), (6, 4),(5,6), (6,5),(6,6)]
3. The probability of getting a 4 = 1/12
4. The probability of getting a 12 = 1/36
Step-by-step explanation:
There are 36 outcomes in all and the event shows the possible numbers obtained after the sum .
The event will be E= [ 2,3,4,5,6,7,8,9,10,11,12]
The random variable X can take any value from( 2,- ----,12) in the event of the sample space.
The sample space S = [(1, 1), (1, 2),(2, 1), (1, 3), (2, 2),(3, 1), (1, 4),(2, 3),(3, 2),(4, 1), (1, 5),(2, 4), (3, 3),(4, 2),(5, 1),(1, 6), (2, 5),(3, 4),(4, 3),(5, 2), (6, 1), (2, 6),(3, 5), (4, 4), (5, 3), (6, 2),(3, 6), (4, 5), (5, 4), (6, 3),(4, 6) (5, 5), (6, 4),(5,6), (6,5),(6,6)]
that is it has all the possible outcomes of both the dice.
The probability of getting a 4= Number of fav outcome/ no of possible outcomes= 3/ 36= 1/12
The probability of getting a 12= Number of fav outcome/ no of possible outcomes=1/36
