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Setler [38]
3 years ago
15

What is the area of triangle ABC?

Mathematics
1 answer:
Zigmanuir [339]3 years ago
6 0

Answer:

i believe it is c: 3.5 if I am correct

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How do i solve each proportion?
natali 33 [55]
You have to cross multiply (multiply the numerator of the first by the denominator of the second and the numerator of the second by the denominator of the first).

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

[19]

\frac{x+4}{3} =  \frac{4}{10}

10x+40=12

10x = -28

x=-2.8

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[21]

\frac{4}{n+8} =  \frac{10}{8}

32 = 8n + 64

8n = -32

n=-4
8 0
3 years ago
Read 2 more answers
What is the distance petween points (5,5) and (1,5) enter the units in the box
goldenfox [79]
(5,5) - (1,5) = (4,5) is the answer
5 0
3 years ago
Please help me! 15 pts! + Brainliest!
WITCHER [35]

Answer:

D

Step-by-step explanation:

It increased 3 meters every second if you look closely at chart

4 0
3 years ago
Robert mixed 113 liters of blue paint with 123 liters of red paint to make 3 liters of purple paint. To make a new batch of purp
MAVERICK [17]

Answer:

Blue =1\frac{3}{5}

Step-by-step explanation:

Given

Blue = 1\frac{1}{3}

Red = 1\frac{2}{3}

Required

Determine the amount of blue paint when Red = 2

To do this, we make use of the following equivalent ratios

Ratio = Blue : Red

When  Blue = 1\frac{1}{3} and  Red = 1\frac{2}{3}

Ratio = 1\frac{1}{3} : 1\frac{2}{3}

When Red = 2

Ratio = Blue : 2

Equate both ratios

Blue : 2 = 1\frac{1}{3} : 1\frac{2}{3}

Convert to division

\frac{Blue}{2} =1\frac{1}{3} / 1\frac{2}{3}

Convert fractions to improper fraction

\frac{Blue}{2} =\frac{4}{3} / \frac{5}{3}

\frac{Blue}{2} =\frac{4}{3} * \frac{3}{5}

\frac{Blue}{2} =\frac{4}{5}

Make Blue the subject

Blue =\frac{4}{5}*2

Blue =\frac{8}{5}

Blue =1\frac{3}{5}

4 0
3 years ago
The difference of two positive numbers is 7 and the sum of their squares is 109. Find the numbers.
Ray Of Light [21]

Answer:

Numbers\ are\ 58\ and\ 51.

Step-by-step explanation:

The the numbers are x\ and\ y.

<em>Difference:</em>

<em></em>Difference\ of\ numbers=7\\\\x-y=7....................eq(1)<em></em>

<em>Sum:</em>

<em></em>Sum\ of\ numbers=109\\\\x+y=109...........................eq(2)<em></em>

<em></em>

Solve eq(1) and eq(2).

eq(1)+eq(2)\\\\x-y+x+y=7+109\\\\2x=116\\\\x=58\\\\Now\ from\ equation\ 1\\\\x-y=7\\\\y=x-7\\\\y=58-7\\\\y=51

7 0
3 years ago
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