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Setler [38]
3 years ago
15

What is the area of triangle ABC?

Mathematics
1 answer:
Zigmanuir [339]3 years ago
6 0

Answer:

i believe it is c: 3.5 if I am correct

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write in scientific  notation 1. 0.0000364 2. 0.00751 3. 0.10005 4. 1,094 5. 0.00000099 6. 0.04101 7. 10,500 8. 8,9000
solmaris [256]
1.\\0\underbrace{.00003}_{5\to}54=3.54\times10^{-5}\\2.\\0\underbrace{.007}_{3\to}51=7.51\times10^{-3}\\3.\\0\underbrace{.1}_{1\to}0005=1.0005\times10^{-1}\\4.\\1\underbrace{,094}_{\leftarrow3}=1.094\times10^3\\5.\\0\underbrace{.0000009}_{7\to}9=9.9\times10^{-7}
6.\\0\underbrace{.04}_{2\to}101=4.101\times10^{-2}\\7.\\1\underbrace{0,500}_{\leftarrow4}=1.05\times10^4\\8.\\8\underbrace{9000}_{\leftarrow4}=8.9\times10^4
3 0
3 years ago
write a two step problem that you can solve using the strategy draw a diagram.explain how can use the strategy to find the solut
nevsk [136]
F(x)=2x+1
you can use a table of values for a diagram and graph the line
3 0
4 years ago
Please help with this I am completely stuck on it
vaieri [72.5K]

Answer:

f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4

Step-by-step explanation:

Given:

The function, H(x)=\sqrt[3]{6x^{2}-4}

Solution 1:

Let f(x)=\sqrt[3]{x}

If f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}, then,

\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4

Solution 2:

Let f(x)=\sqrt[3]{x-4}. Then,

f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}

Similarly, there can be many solutions.

7 0
3 years ago
what is the equation to seven less than the product of twice a number is greater than 5 more than the same number
postnew [5]
<span>seven less than (-7) than the product of twice a number (2x) is greater than (>) five more than (+5) the same number (x)

2x-7>x+5
treat the > sign as an equals for now
2x-7=x+5
subtract x from both sides
x-7=5
add 7 to both sides
x=12
put the > sign back in
x>12</span>
7 0
4 years ago
Read 2 more answers
X<br> ſocm<br> Jicm<br> A) 2V5 cm<br> B) V13 cm<br> D) V19 cm<br> C) 1 cm<br> ASAP
bulgar [2K]

Answer:

using pythagoras theorem

hyp 2=opp 2+adj 2

=( √6)(√6)+(√7)(√7)

hyp 2=13

hyp=√13

3 0
3 years ago
Read 2 more answers
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