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3 years ago

Given the table, what is the y-intercept of the linear function?

Mathematics

1 answer:

motikmotik3 years ago

6 0

Step-by-step explanation:

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The graph of y = f(x) is the solid black graph below. Which function represents the dotted graph?

Zigmanuir [339]

Answer:

y = -f(x - 5)

Step-by-step explanation:

the function of the dotted graph is f(x) shifted (or translated) 5 units to the right and then reflected across the x-axis.

shifting it to the right is happening by reducing every x value by 5 (so that we get for x the functional value of x-5).

and reflecting it across the x-axis simply means to flip the sign. everything that was originally above the x-axis is now with the same distance below the x-axis (and vice versa).

therefore, the new

y = -f(x - 5)

5 0

2 years ago

The photography club has 28 members. There are 12 boys in the club. What is the ratio of boys to girls in simplest form?

Molodets [167]

Steps:
1. Do 28-12= 16 girls
2. Your ratio is 12:16
3. Your answer is B. 3/4
4. This correct because
12 divided by 4 is 3
16 divided by 4 is 4
5. Your answer is 3/4

8 0

4 years ago

Read 2 more answers

Jason is buying baseball cards.Each packet of baseball cards contains 12 baseball cards and costs $3.How many baseball cards can

dalvyx [7]

15 divided by 3 is 5, so he can buy 5 packs.
Since each pack contains 12 cards, 12x5=60.

6 0

3 years ago

HELP PLEASE SIMPLIFY !!!

Lelechka [254]

Answer:

$=x^{\frac{5}{6}}+2x^{\frac{7}{3}}$

Step-by-step explanation:

$x^{\frac{1}{3}}\left(x^{\frac{1}{2}}+2x^2\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=x^{\frac{1}{3}},\:b=x^{\frac{1}{2}},\:c=2x^2\\=x^{\frac{1}{3}}x^{\frac{1}{2}}+x^{\frac{1}{3}}\cdot \:2x^2\\=x^{\frac{1}{3}}x^{\frac{1}{2}}+2x^2x^{\frac{1}{3}}\\\mathrm{Simplify}\:x^{\frac{1}{3}}x^{\frac{1}{2}}+2x^2x^{\frac{1}{3}}:\quad x^{\frac{5}{6}}+2x^{\frac{7}{3}}\\x^{\frac{1}{3}}x^{\frac{1}{2}}+2x^2x^{\frac{1}{3}}\\x^{\frac{1}{3}}x^{\frac{1}{2}}=x^{\frac{5}{6}}$

$x^{\frac{1}{3}}x^{\frac{1}{2}}\\\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}\\x^{\frac{1}{3}}x^{\frac{1}{2}}=\:x^{\frac{1}{3}+\frac{1}{2}}\\=x^{\frac{1}{3}+\frac{1}{2}}\\\mathrm{Join}\:\frac{1}{3}+\frac{1}{2}:\quad \frac{5}{6}\\\frac{1}{3}+\frac{1}{2}\\\mathrm{Least\:Common\:Multiplier\:of\:}3,\:2:\quad 6\\Adjust\:Fractions\:based\:on\:the\:LCM\\=\frac{2}{6}+\frac{3}{6}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}\\=\frac{2+3}{6}\\\mathrm{Add\:the\:numbers:}\:2+3=5\\=\frac{5}{6}\\=x^{\frac{5}{6}}\\2x^2x^{\frac{1}{3}}=2x^{\frac{7}{3}}\\=x^{\frac{5}{6}}+2x^{\frac{7}{3}}$

7 0

3 years ago

Being timed help

Makovka662 [10]

I'm assuming 43 is actually 4/3
see what number the previous term must be multiplied by to get the next term
4 *something = 12, 12*something=36
common ratio is 3

6 0

4 years ago