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nlexa [21]
3 years ago
11

What would have to be done to put 3x (2x - 7) =9 in standard form? Group of answer choices

Mathematics
1 answer:
Artemon [7]3 years ago
3 0

Answer:

B

Step-by-step explanation:

You might be interested in
Can someone help me with this ????
fenix001 [56]

Answer:

A.

(\frac{3}{3+5})(2 - (-14))+ (-14)

Step-by-step explanation:

Given

Ratio = 3:5

Q = -14

S = 2

Required

Which solution uses (\frac{m}{m+n})(x_2 - x_1)+ x_1

From the given parameters;

m:n = 2:5

m = 2\ and\ n = 5

x_1 = -14\ and\ x_2 = 2

Substitute the above values in (\frac{m}{m+n})(x_2 - x_1)+ x_1

This gives:

(\frac{m}{m+n})(x_2 - x_1)+ x_1

(\frac{3}{3+5})(2 - (-14))+ (-14)

<em>From the list of given options, only option A uses the given form of the formula...</em>

6 0
3 years ago
The length of a rectangle is 3cm more than the width. The area is 70cm^2. Find the dimensions of the rectangle​
Rom4ik [11]
Let width be x
Length would be x + 3
Area = L * W
Make an equation
(x) * (x+3) = 70
x^2 + 3x = 70
x^2 + 3x - 70 = 0
Quadratic formula
(-3 +/- rt 3^2 - 4 * 1 * (-70))/(2 * 1)
x1 = (-3 + 17)/2, x2 = (-3-17)/2
x = 7, x = -10
Dimension cannot be negative

Solution: width = 7
Length = 10
7 0
3 years ago
In which step did Samuel make an error?
FrozenT [24]

Answer:

In step 3

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Equation 4x - 9 = 7x + 12 explanation please
dedylja [7]

Answer:

x=-7

Step-by-step explanation:

first, subtract 4x from both sides. then you'll get:

-9=3x+12

next subtract 12 from both sides. Then you'll get:

-21=3x

then you divide each side by 3. You get:

x=-7

8 0
3 years ago
Determine the maximum value of the objective function, P.
Ad libitum [116K]

Answer:

Maximum (250,125) Answer

Step-by-step explanation:

This is more of a graphing problem than it is anything else.

Begin by graphing all 4 given equations.

When you do that, mark the intersection points of at least 2 lines. In this case it is exactly 2 lines for each intersecting point.

6x + 4y <= 2000 and 2x + 4y <= 1000 intersect at (250,125)

x=>0 and y=>0 intersect at (0,0)

6x + 4y <=2000 and x => 0 intersect at 333.333

2x + 4y <=1000 and y>=0 intersect at  0,250.

Any other intersection points fall outside the range of the givens. The shaded part we are interested in is sort of a very dark green/blue. It is the interior of the quadrilateral determined by the 4 vertices that are marked.

Now all you have to do is determine the maximum point using P=15x + 12y

For 0,0                 P = 15*0 + 12,0 = 0

For 0,250            P = 15*0 + 12*250 = 3000

For 333.3333,0   P = 15*333.3333 + 12*0 = 5000 rounded.

For 250,125        P = 15*250 + 12*125 = 5250  Which is the maximum

Answer (250,125) produces the maximum value Answer

5 0
3 years ago
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