Answer:
Percent error is approx. 22%
Step-by-step explanation:
So to do this you need to know the formula for percent error, which is
percent error = l measured - theoretical / theoretical l * 100%
With this just plug in 18 (real) and 14 (measured).
percent error = l 14 - 18 / 18 l * 100%
percent error = l -4 / 18 l *100%
percent error = l -2/9 l *100%
You then do absolute value because the percent error must be positive not negative! So -2/9 becomes 2/9. You then divide 2/9 to get approx. 0.22... and you muliply by 100% to get 22%.
Answer:
v=-3/5
Step-by-step explanation:
9 = v + 4 v + 12
=>5v=9-12
=>v=-3/5
The intensity of sound which the decibel level of the sound measures 156 is 3.981 × 10³ W/m²
Decibel level, dB = 10log₁₀(I/I₀) where dB = decibel level = 156, I = intensity at 156 dB and I₀ = 10⁻¹² W/m².
Since we require I, making I subject of the formula, we have
dB/10 = log₁₀(I/I₀)
Substituting the values of the variables into the equation, we have
I = 3981.072W/m²
I = 3.981 × 10³ W/m²
So, the intensity of sound which the decibel level of the sound measures 156 is 3.981 × 10³ W/m²
Learn more about intensity of sound here:
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