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3 years ago

Make an equation to solve this problem:

Mathematics

1 answer:

svetlana [45]3 years ago

5 0

B=a+6
b+a=42
susitute
a+6+a=42
subtract 6
2a=36
divide 2
a=18
subisute
b=18+6=24

b=24
a=18

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How are Ratios,rates and unit rates used to solve problems?

insens350 [35]

Answer:

hope u understand

Step-by-step explanation:

Unit rates can conveniently be multiplied by any desired number in order to answer questions about differently scaled questions. E.g. If three marbles cost 30 cents, how much will eleven marbles cost?

A unit rate is a ratio such as 30 cents : 3 marbles = 10 cents per (1) marble, after doing the division.

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3 years ago

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Please help, will mark brainliest!! thanks

Mars2501 [29]

Answer:

39.43 for each dog

Step-by-step explanation:

<u>d = 2c (given) </u>

164 c + 23 d = 4140 sub in the above equation for d

164 c + 23<u> (2c)</u> = 4140

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2 years ago

We often deal with weighted means, in which different data values carry different weights in the calculation of the mean. For

Veseljchak [2.6K]

Answer:

a) The student's overall average for the class is 87.97.

b) He would need a score above 100 to get an A, which means that he could not have scored high enough on the final exam to get an A in the class.

Step-by-step explanation:

Weighed average:

To solve this question, we find the student's weighed average, multiplying each of his grade by his weights.

Grades and weights:

Scored 82.5 on the midterm, worth 30%.

Scored 88.6 on the final exam, worth 30%.

Scored 91.6 on the homework, worth 40%.

a. On a 100-point scale, what is the student's overall average for the class?

Multiplying each grade by it's weight:

$A = 82.5*0.3 + 88.6*0.3 + 91.6*0.4 = 87.97$

The student's overall average for the class is 87.97.

b. The student was hoping to get an A in the class, which requires an overall score of 93.5 or higher. Could he have scored high enough on the final exam to get an A in the class?

Score of x on the final class, and verify that the average could be 93.5 or higher. So

$A = 82.5*0.3 + 88.6*0.3 + 0.4x$

$A \geq 93.5$

$82.5*0.3 + 88.6*0.3 + 0.4x \geq 93.5$

$0.4x \geq 93.5 - (82.5*0.3 + 88.6*0.3)$

$x \geq \frac{93.5 - (82.5*0.3 + 88.6*0.3)}{0.4}$

$x \geq 105.425$

He would need a score above 100 to get an A, which means that he could not have scored high enough on the final exam to get an A in the class.

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3 years ago

What is the solution to the inequality

Dvinal [7]

Answer:

p > 5 and p <-8

Step-by-step explanation:

To solve this, you first need to isolate p.

First add 6 on both sides of the equation:

$-6 + |2p+3| >7\\\\(+6) -6 + |2p+3| >7 +6\\\\2p + 3 > 13$

Then subtract 3 from both sides of the equation.

$2p+3-3>13-3\\\\2p > 10\\$

The divide both sides by 2.

$\dfrac{2p}{2}>\dfrac{10}{2}\\\\p>5$

Another solution is possible because of the absolute value.

If $|2p+3|>13$

Then $|2p+3|$

<em>Thus we can solve the second solution:</em>

$|2p+3|$

$2p+3$

Isolate P again by subtracting both sides by 3

$2p+3-3$

$2p$

Then divide both sides by 2:

$\dfrac{2p}{2}$

$p$

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4 years ago

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igor_vitrenko [27]

Answer: Y=-1 or Y=-1+4

Step-by-step explanation:

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