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3 years ago

-x^(2)-12=-87 Please explain your answer, and how I make the x positive

1 answer:

7 0

Solve for x over the real numbers:
-x^2 - 12 = -87
Add 12 to both sides:
-x^2 = -75
Multiply both sides by -1:
x^2 = 75
Take the square root of both sides:
Answer: x = 5 sqrt(3) or x = -5 sqrt(3) both Answers are correct

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Mrs. Bailey gives a test, and her students’ scores range from 30 to 70. She decides to curve the scores, so that they range from

Harman [31]

Answer:

f(x) = x*3/4 + 42.5

Step-by-step explanation:

The original difference between the pair is 70 - 30 = 40

The new difference between the pair is 95 - 65 = 30

Since the differences are not the same, Mrs Bailey must first perform a (slope) multiplication by a factor of 30/40 or 3/4

Then 30 * 3/4 = 22.5

Then she can shift the scores up by 65 - 22.5 = 42.5 in order to get the range from 65 to 95

Therefore, f(x) = x*3/4 + 42.5. We can test that

f(30) = 30*3/4 + 42.5 = 65

f(70) = 70*3/4 + 42.5 = 95

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2 years ago

What is the variable of 18+t

Dmitry_Shevchenko [17]

T because all variables are letters

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2 years ago

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Joseph has saved $500. He has to pay his mom $25 a month for his phone, but he wants to have at least $200 left to pay for a new

irakobra [83]

Answer:

500-200=300 300 divided by 25 give you x, the number of months

Step-by-step explanation:

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1 year ago

Safeway has ginger ale on sale at 12 cans for $4.00 and Giant has the same brand

Genrish500 [490]

Answer:

Giant has the better deal

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2 years ago

In equilateral ΔABC, AD, BE, and CF are medians. If FO = 4, then AE = A) 4 B) 4 3 C) 8 D) 12

vampirchik [111]

Firstly, we need to draw triangle

we know that

O is a centroid

and centroid divides median into 2:1

so,

$\frac{CO}{FO} =\frac{2}{1}$

we have FO=4

so, we can plug it

$\frac{CO}{4} =\frac{2}{1}$

$CO=8$

now, we can find CF

CF=OC+FO

CF=8+4

CF=12

now, we can see triangle ACF is a right angled triangle

so, we can use pythagoras theorem

$x^2=(\frac{x}{2} )^2+12^2$

now, we can solve for x

$\frac{3x^2}{4}=144$

$x^2=192$

$x=8\sqrt{3}$

Since, it is equilateral triangle

so,

$AC=x=8\sqrt{3}$

we know that

E is a mid-point

so,

$AE=\frac{AC}{2}$

now, we can plug values

$AE=\frac{8\sqrt{3}}{2}$

$AE=4\sqrt{3}$ ................Answer

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2 years ago

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