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viktelen [127]
3 years ago
10

Ingrid is moving a box from the ground into the back of a truck. She uses 20 N of force to move the box

Mathematics
2 answers:
3241004551 [841]3 years ago
8 0

She will decrease the amount of work

Without the ramp, Ingrid would have to, in no particular order,

• push the box along the ground, which amounts of (20 N) (5 m) = 100 J of work

• lift the box up some height <em>h</em> with a force at least equal in magnitude to the weight of the box <em>mg</em>, so that the work done in the lifting is <em>mgh</em> (i.e. the energy required to lift the box with constant speed to a height <em>h</em>)

and the total work done in this way would be (100 + <em>mgh</em>) J.

With the ramp, Ingrid would instead push the box a length equal to the hypotenuse of the right triangle formed by the two displacements above. Recall that the hypotenuse of any right triangle is always shorter than the sum of its legs' lengths. (This eliminates the third and fourth options.) So if the length of the ramp, or total displacement of the box along the ramp, is <em>s</em>, then the work done by pushing up the ramp is (10 N) <em>s</em> = 10<em>s</em> J

DerKrebs [107]3 years ago
3 0

Answer:

hi

Step-by-step explanation:

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Sally finds a coin with a radius of 1.5 centimeters and a thickness of 0.25 cm. It has a measured mass of 18.54 grams. How can S
mote1985 [20]

Answer:

Silver

Step-by-step explanation:

Find the volume of the coin

<u>Volume of a cylinder</u>

\textsf{V}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}

Given:

  • r = 1.5 cm
  • h = 0.25 cm

Substituting given values into the formula to find the volume:

\sf \implies V=\pi (1.5)^2(0.25)

\sf \implies V=0.5625 \pi \:cm^3

Find the density of the coin given it has a measured mass of 18.54 g

<u>Density formula</u>

\sf \rho=\dfrac{m}{V}

where:

  • \rho = density
  • m = mass
  • V = volume

Given:

  • m = 18.54 g
  • \sf V=0.5625 \pi \:cm^3

Substituting given values into the density formula:

\implies \sf \rho=\dfrac{18.54}{0.5625 \pi}

\implies \sf \rho=10.49149385\:g\:cm^{-3}

Given:

  • \textsf{Density of Lead}=\sf 11.3\:g\:cm^{-3}
  • \textsf{Density of Silver}=\sf 10.49\:g\:cm^{-3}

Therefore, as \sf \rho=10.49\:g\:cm^{-3} the coin is made from silver.

4 0
2 years ago
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