Question

A golf ball (mass 0.045 kg) is hit with a club from a tee. The plot shows the force on the ball as a function of time in milliseconds. One millisecond is 10-3 seconds. What is its speed right after the hit

Answer 1

Answer:

16.3 m/s

Explanation:

We are given that

Mass of golf ball=m=0.045 kg

We have to find the speed right after the hit.

$b_1=(16-1)\times 10^{-3}=15\times 10^{-3} s$

$b_2=(12-6)\times 10^{-3}=6\times 10^{-3} s$

Force,F=70 N

Change in momentum=Area of trapezium

Area of trapezium,A=$\frac{1}{2}(b_1+b_2) h$

Using the formula

$m(v-u)=\frac{1}{2}(15+6)\times 10^{-3}\times 70$

$0.045(v-u)=\frac{1}{2}(21)\times 10^{-3}\times 70$

$v-u=\frac{1}{2}\times \frac{1}{0.045}\times 21\times 10^{-3}\times 70$

$v-u=16.3$

Initial velocity of golf ball=u=0

$v-0=16.3$

$v=16.3 m/s$